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3 years ago

can someone help me with the 6 questions I'm sorry I know it's hard to see and I will tell you the questions

Mathematics

2 answers:

Sveta_85 [38]3 years ago

6 0

1. 9
2. 9
3. ??
4. 12:15
5. Cant see
6. 8

just olya [345]3 years ago

3 0

1. 9
2. 3 (This problem is explained on brainly here: brainly.com/question/485726)
3. Triangle because a lateral face is any face that is not a base.
4. 2:15. You first add three hours, then, 1/4 of an hour is 15 minutes. You multiply 15*3 because you're trying to find 3/4 of an hour. Then you have to add that to the current 30 minutes.
5. I can't see it, sorry. :(
6. 8. First, you have to find out how many inches are in 50 feet (50*12). Then, you divide that number by 75 to figure out how many rotations.

You might be interested in

What is sin -1 (1/2) if the terminal side of 0 is located in quadrant 1

Lady_Fox [76]

Answer:

sin^-1 (1/2) = 30°

Step-by-step explanation:

* Lets explain how to find the trigonometry functions from the unit circle

- The unit circle is the circle whose radius is 1 unit

- It intersects the four axes at:

# Positive part of x-axis at (1 , 0) and negative part at (-1 , 0)

# Positive part of y-axis at (0 , 1) and negative part at (0 , -1)

- The terminal of any angle intersect it at point (x , y) where x² + y² = 1

- If The angle between the terminal side and the x-axis is Ф , then

# The adjacent side of Ф = x

# The opposite side of the angle Ф = y

- In the problem the terminal side lies in the first quadrant

∴ all the trigonometry functions are positive

∵ sin Ф = opposite/hypotenuse

∵ The opposite = 1/2 and the hypotenuse is the terminal side = 1

∴ sin Ф = 1/2 ÷ 1 = 1/2

- To find Ф use the inverse function sin^-1 Ф

∵ sin Ф = 1/2

∴ Ф = sin^-1 (1/2)

∴ Ф = 30°

* sin^-1 (1/2) = 30°

6 0

3 years ago

The Cowboys High School Band Boosters are selling candy bars and chips at the basketball tournament to raise money for their ban

masya89 [10]

Answer:

They have 425 candy bars ready to sell.

Step-by-step explanation:

Let,

x be the number of candy bars ready to sell

y be the number of chips ready to sell

According to given statement;

x+y=575 Eqn 1

x+0.5y= 500 Eqn 2

Subtracting Eqn 2 from Eqn 1

(x+y)-(x+0.5y)=575-500

x+y-x-0.5y=75

0.5y = 75

Dividing both sides by 0.5

$\frac{0.5y}{0.5}=\frac{75}{0.5}\\y=150$

Putting y=150 in Eqn 1

x+150 = 575

x = 575-150

x = 425

Hence,

They have 425 candy bars ready to sell.

7 0

3 years ago

How would I solve I need to know Asap and what is the answer

masha68 [24]

Answer:

True; True; False; True

Step-by-step explanation:

4 0

2 years ago

Simplify using the vertical method. (3k + 4)(3k^2 – 5k – 3)

liubo4ka [24]

Answer:

$9k^{3} -3k^{2}-29k-12$

Step-by-step explanation:

Step 1: Expand by distributing sum groups.

$3k(3k^{2} -5k-3)+4(3k^{2} -5k-3)$

Step 2: Expand by distributing terms.

$9k^{3} -15k^{2} -9k+4(3k^{2} -5k-3)$

Step 3: Expand by distributing terms.

$9k^{3}-15k^{2} -9k+12k^{2} -20k-12$

Step 4: Collect like terms.

$9k^{3}+(-15k^{2} +12k^{2} )+(-9k-20k)-12$

Step 5: Simplify.

$9k^{3} -3k^{2}-29k-12$

3 0

3 years ago

Please help I need help with my hw

olga2289 [7]

Answer:

a) 2.5 pounds of candy

b) 2.5 pounds of candy

$\frac{0.5}{1} :\frac{y}{5}$

y × 1 = 0.5 × 5

y = 2.5

Step-by-step explanation:

1 = 5

1/2 = y or 0.5 = y

$\frac{0.5}{1} :\frac{y}{5}$

y × 1 = 0.5 × 5

y = 2.5

7 0

3 years ago