Answer:
We need a sample size of 564.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.

In which
z is the zscore that has a pvalue of
.
For this problem, we have that:

The margin of error is:

95% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.
We need a sample size of n
n is found when 
So






Rounding up
We need a sample size of 564.
2*l*w+2*l*h+2*w*h plug in then solve
Answer:

Step-by-step explanation:
= 
2*(pq)= 2(
)= 
-3
= -3
= 
=
=

Answer:
155
Step-by-step explanation:
Remember that below sea level means negative. So 120-(-35)=155
I hope this helps! :)
10% of 14 =1.4
14-1.4=12.6
6% of 14=0.84
12.6+0.84= 13.45