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2 years ago

Determine which number has the lesser of the magnitude.

Mathematics

1 answer:

mario62 [17]2 years ago

6 0

Answer:

Notice that <u>negative numbers</u> begin towards the left of the 0 on the number line. On the number line, as you go towards the left, numbers get smaller. When you go towards the right, numbers get larger. That means the higher the negative number, the smaller its relative magnitude.

Step-by-step explanation:

hope it helps

mark me brainliest pls

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You downloaded a video game to your computer.You have 60-minute free trail of the game.It takes 5 minutes to set up the game and

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3 years ago

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Softa [21]

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1 year ago

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There were 99 tulips in the field. Only 3/9 bloomed. How many tulips bloomed? How many did not bloom?

Ratling [72]

Answer: 33 tulips bloomed / 66 tulips did not bloom

Step-by-step explanation:

<h2>Given:</h2>

Total number of tulips = 99

Total number of tulips bloomed = 3/9 of total

<h2>Solve:</h2>

Step One: Find the number of tulips that bloomed

99 × (3/9) = 99 × (1/3) = 33 tulips

Step Two: Find the number of tulips that did not bloom

99 - 33 = 66 tulips

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3 years ago

A probability experiment is conducted in which the sample space of the experiment is upper s equals startset 4 comma 5 comma 6 c

olchik [2.2K]

The correct question statement is:

A probability experiment is conducted in which the sample space of the experiment is S = {4,5,6,7,8,9,10,11,12,13,14,15}. Let event E={7,8,9,10,11,12,13,14,15}. Assume each outcome is equally likely. List the outcomes in $E^{c}$ . Find $P(E^{c})$ .

Solution:

Part 1:

$E^{c}$ means compliment of the set E. A compliment of a set can be obtained by finding the difference of the set from the universal set. The universal set is the set which contains all the possible outcomes of the events which is S in this case.

So, compliment of E will be equal to S - E. S - E will result in all those elements of S which are not present in E. So, we can write:

$E^{c}=S-E \\ \\ 
E^{c}=(4,5,6,7,8,9,10,11,12,13,14,15)-(7,8,9,10,11,12,13,14,15) \\ \\ 
E^{c}=(4,5,6)$

Thus the set compliment of E will contain the elements {4,5,6}.So

$E^{c}$ = {4,5,6}

Part 2)

$P(E^{c})$ means probability that if we select any number from the Sample Space S, it will belong the set E compliment.

$P(E^{c})$ = (Number of Elements in $E^{c}$ )/Number of elements in S

Number of elements in set S = n(S) = 12
Number of elements in set $E^{c}$ = $n(E^{c})$ =3

So,

$P(E^{c})= \frac{n(E^{c}) }{n(S)} \\ \\ 
P(E^{c})= \frac{3}{12} \\ \\ 
P(E^{c})= \frac{1}{4}$

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Answer:

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