Volume
of a rectangular box = length x width x height<span>
From the problem statement,
length = 60 - 2x
width = 10 - 2x
height = x</span>
<span>
where x is the height of the box or the side of the equal squares from each
corner and turning up the sides
V = (60-2x) (10-2x) (x)
V = (60 - 2x) (10x - 2x^2)
V = 600x - 120x^2 -20x^2 + 4x^3
V = 4x^3 - 100x^2 + 600x
To maximize the volume, we differentiate the expression of the volume and
equate it to zero.
V = </span>4x^3 - 100x^2 + 600x<span>
dV/dx = 12x^2 - 200x + 600
12x^2 - 200x + 600 = 0</span>
<span>x^2 - 50/3x + 50 = 0
Solving for x,
x1 = 12.74 ; Volume = -315.56 (cannot be negative)
x2 = 3.92 ;
Volume = 1056.31So, the answer would be that the maximum volume would be 1056.31 cm^3.</span><span>
</span>
It's a number less than 5.
The first two are correct because you have to understand and the questions are right good job w8th it
Answer:
-16y+2yx
Step-by-step explanation:
Answer:
50%
Step-by-step explanation:
10 kg of mixed nuts that contain 60% peanuts
60(10)
plus
15 kg of a different brand of mixed nuts. with x% peanuts
x(15)
=
That makes 25 kg with 54% peanuts
54(25)
--------------------------
Equation
60(10) + x(15) = 54(25)
600 + 15x = 1350
Subtract 600 from both sides
15x = 750
Diviede both sides by 15
x = 50
50%
