9 999 999 in words is read as nine million, nine hundred and ninety-nine thousand, and nine hundred and ninety-nine
By partitioning, we can write 9 999 999 as follow
9 000 000 + 900 000 + 90 000 + 9000 + 900 + 90 + 9
If we start at the first digit of '9' on the left, the next digit is ten times smaller than the previous one.
Answer: 144
Step-by-step explanation: The problem shown here can be read as "10 to the 2nd," oe "12 to the 2nd power."
The 12 is called the base and the 2 that is raised up is called the exponent.
The exponent of 2 tells us that we multiply our base 2 times.
So we have 12 · 12 which is 144.
The numbers that we multiply together are called factors so in this problem, we have 2 factors of 12.
Answer: The required three consecutive odd integers are 7, 9 , 11.
Step-by-step explanation:
Let x , x+2 , x+4 be the three consecutive odd integers.
As per given ,
10(x) = 59+x+4
⇒10x= 59+x+4
⇒ 9x= 63
⇒ x= 7 [ divide both sides by 7]
Hence, the required three consecutive odd integers are 7, 9 , 11.
Step-by-step explanation:
25 is the answer . hope it helps