Because the actual dimensions of the board and the target are missing, let us supply the missing values.
Let:
radius of board = 6 inches
radius of target = 2 inches
Area of board = pi * r^2 = pi*6^2 = 36pi
Area of target = pi * r^2 = pi*2^2 = 4pi
Probability of hitting the target = 4pi / 36pi = 1/9
Therefore, there is a 1/9 chance of hitting the target on the board.
Answer:
d=117.33 m
Step-by-step explanation:
Initial velocity of planes, u = 0 (because they are at rest)
Acceleration, a = 3.3 m/s²
Final take off speed, v = 88 m/s
We need to find the minimum allowed length for the runway. Let it is d. d will be the distance. It can be calculated using third equation of motion as follows :

Putting all the values, we get :

Hence, the minimum allowed length for the runway is 117.33 m.
Answer:
Algebraic Expression
Step-by-step explanation:
It's an algebraic expression because there's variables.
The variable is y :)
Answer: around 86.3
Step-by-step explanation: