Sin³ x-sin x=cos ² x
we know that:
sin²x + cos²x=1 ⇒cos²x=1-sin²x
Therefore:
sin³x-sin x=1-sin²x
sin³x+sin²x-sin x-1=0
sin³x=z
z³+z²-z-1=0
we divide by Ruffini method:
1 1 -1 -1
1 1 2 1 z=1
-------------------------------------
1 2 1 0
-1 -1 -1 z=-1
--------------------------------------
1 1 0 z=-1
Therefore; the solutions are z=-1 and z=1
The solutions are:
if z=-1, then
sin x=-1 ⇒x= arcsin -1=π+2kπ (180º+360ºK) K∈Z
if z=1, then
sin x=1 ⇒ x=arcsin 1=π/2 + 2kπ (90º+360ºK) k∈Z
π/2 + 2kπ U π+2Kπ=π/2+kπ k∈Z ≈(90º+180ºK)
Answer: π/2 + Kπ or 90º+180ºK K∈Z
Z=...-3,-2,-1,0,1,2,3,4....
1/ 1/5
1/1÷1/5
1/1×5/1
5/1=
5
Answer:
b
Step-by-step explanation:
1/2 *(a+b)-(a-b)²
a=18, b=14
1/2 *(18+14)-(18-14)²=1/2 *(18+14)-(18-14)²= 1/2*32-4²=16-16=0
answer D
answer B
2 factors have 2 terms: (x+4) and (y+4)
Well, let's see how it'll effect your grade...
75% ÷ 90% = 0.83
0.83 x 100 = 83%
It would effect your grade by 7 percent, lowering it to 83%
I hope this helps!
