This is basically my last question so please help
1 answer:
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Answer:
y=5, y=
Step-by-step explanation:
Hi there!
We are given the equation
+
=
and we need to solve for y
first, we need to find the domain, which is which is the set of values that y CANNOT be, as the denominator of the fractions cannot be 0
which means that y-3≠0, or y≠3, and y-4≠0, or y≠4
and
are algebraic fractions, meaning that they are fractions (notice the fraction bar), but BOTH the numerator and denominator have algebraic expressions
Nonetheless, they are still fractions, and we need to add them.
To add fractions, we need to find a common denominator
One of the easiest ways to find a common denominator is to multiply the denominators of the fractions together
Let's do that here;
on , multiply the numerator and denominator by y-4
; simplify by multiplying the binomials together using FOIL to get:
Now on , multiply the numerator and denominator by y-3
; simplify by multiplying the binomials together using FOIL to get:
now add and
together
Remember: since they have the same denominator, we add the numerators together
simplify by combining like terms
the result is:
remember, that's set equal to
here is our equation now:
=
it is a proportion, so you may cross multiply
2(2y²-6y-5)=15(y²-7y+12)
do the distributive property
4y²-12y-10=15y²-105y+180
subtract 4y² from both sides
-12y-10=11y²-105y+180
add 12 y to both sides
-10=11y²-93y+180
add 10 to both sides
11y²-93y+190=0
now we have a quadratic equation
Let's solve this using the quadratic formula
Recall that the quadratic formula is y=(-b±√(b²-4ac))/2a, where a, b, and c are the coefficients of the numbers in a quadratic equation
in this case,
a=11
b=-93
c=190
substitute into the formula
y=(93±√(8649-4(11*190))/2*11
simplify the part under the radical
y=(93±√289)/22
take the square root of 289
y=(93±17)/22
split into 2 separate equations:
y=
y=
y=5
and:
y=
y=
y=
Both numbers work in this case (remember: the domain is y≠3, y≠4)
So the answer is:
y=5, y=
Hope this helps! :)