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2 years ago

A pair of Jeans cost $88 A jeans jackets cost twice as much What is the cost of a Jean jacket and 4 pairs of jeans

Mathematics

2 answers:

blagie [28]2 years ago

8 0

Answer:

$528

Step-by-step explanation:

$88 x 4 to find the cost of total amount of jeans

$88 x 2 for total cost of jean jacket

Add both together to find total amount

Dominik [7]2 years ago

4 0

You already found what jeans cost. Now all you have to find is the cost of the jean jacket

88*2 = 176.

Now you have to multiply 4 onto the 88. Your answer is 352.

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Calculate the probability of flipping a coin 20 times and getting 4 heads. Round your answer to the nearest ten thousandth.

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Answer:

0.0046

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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2 years ago

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90 hazelnuts have a mass of 125 g. Hazelnuts have 630 calories per 100 g. work out the number of calories per hazelnut

jenyasd209 [6]

90 hazelnuts = 125g

Therefore, the mass of one hazelnut is this...

90 / 90 = 125 / 90

1 hazelnut = 25/18 grams

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100 divided by 25/18 = 72

Therefore...

630 / 72 = 1 hazelnut

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3 years ago

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One satellite is scheduled to be launched from Cape Canaveral in Florida, and another launching is scheduled for Vandenberg Air

Lisa [10]

Answer:

$P(A) = 0.45$

$P(B) = 0.32$

Step-by-step explanation:

Given

$P(A) > P(B)$

$P(A\ u\ B) = 0.626$

$P(A\ n\ B) = 0.144$

Required

Find P(A) and P(B)

We have that:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

and

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

The equations become:

$P(A\ u\ B) = P(A) + P(B) - P(A\ n\ B)$ --- (1)

$0.626 = P(A) + P(B) - 0.144$

Collect like terms

$P(A) + P(B) = 0.626 + 0.144$

$P(A) + P(B) = 0.770$

Make P(A) the subject

$P(A) = 0.770 - P(B)$

$P(A\ n\ B) = P(A) * P(B)$ --- (2)

$0.144 = P(A) * P(B)$

$P(A) * P(B) = 0.144$

Substitute: $P(A) = 0.770 - P(B)$

$[0.770 - P(B)] * P(B) = 0.144$

Open bracket

$0.770P(B) - P(B)^2 = 0.144$

Represent P(B) with x

$0.770x - x^2 = 0.144$

Rewrite as:

$x^2 - 0.770x + 0.144 = 0$

Expand

$x^2 - 0.45x - 0.32x + 0.144 = 0$

Factorize:

$x[x - 0.45] - 0.32[x - 0.45]= 0$

Factor out x - 0.45

$[x - 0.32][x - 0.45]= 0$

Split

$x - 0.32= 0 \ or\ x - 0.45= 0$

Solve for x

$x = 0.32\ or\ x = 0.45$

Recall that:

$P(B) = x$

So, we have:

$P(B) = 0.32 \ or \ P(B) = 0.45$

Recall that:

$P(A) = 0.770 - P(B)$

So, we have:

$P(A) = 0.770 - 0.32 \ or\ P(A) =0.770 - 0.45$

$P(A) = 0.45 \ or\ P(A) =0.32$

Since:

$P(A) > P(B)$

Then:

$P(A) = 0.45$

$P(B) = 0.32$

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2 years ago

a copy machine makes 60 copies per minute. a second copy makes 80 copies per minutes. the second machine starts making copies 2

wel

8minutes-2minutes=6minutes
6×80 copies = 480 copies

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3 years ago