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3 years ago

6

Pam is painting a total of 45 square feet in her bedroom. If she has painted 60% so far, how many square feet of the bedroroom d

oes Pam still need to paint?

2 answers:

Leno4ka [110]3 years ago

6 0

Since she has painted 60% of her bedroom so far, 40% must remain. In order to know how many square feet that is, we take the total amount of square feet she needs to paint and multiply it by 0.4

45*0.4 = 18 square feet

xenn [34]3 years ago

3 0

To find the answer:

60% of 45 = 27
45 - 27 = 18

Or:

40% of 45 = 18

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3 years ago

<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%28-81%29x%5E%7B2%7D%20%7D" id="TexFormula1" title="\sqrt{(-81)x^{2} }" alt="\sqrt{(

SSSSS [86.1K]

Answer:

We conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

Step-by-step explanation:

Given the radical expression

$\sqrt{\left(-81\right)x^2}$

simplifying the expression

$\sqrt{\left(-81\right)x^2}$

Remove parentheses: (-a) = -a

$\sqrt{\left(-81\right)x^2}=\sqrt{-81x^2}$

Apply radical rule: $\sqrt{-a}=\sqrt{-1}\sqrt{a},\:\quad \mathrm{\:assuming\:}a\ge 0$

$=\sqrt{-1}\sqrt{81x^2}$

Apply imaginary number rule: $\sqrt{-1}=i$

$=i\sqrt{81x^2}$

Apply radical rule: $\sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b},\:\quad \mathrm{\:assuming\:}a\ge 0,\:b\ge 0$

$=\sqrt{81}i\sqrt{x^2}$

$=9i\sqrt{x^2}$

Apply radical rule: $\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$=9ix$

Therefore, we conclude that:

$\sqrt{\left(-81\right)x^2}=9ix$

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3 years ago

When a constant force is applied to an object, the acceleration of the object varies inversely with its mass. When a certain con

marusya05 [52]

Answer: The mass of the object is 10 kg

Step-by-step explanation:

According to Newton's second law of motion, the force $F$ applied to an object with mass $m$ is directly proportional to its acceleration $a$ :

$F=ma$ (1)

If we isolate $a$ :

$a=\frac{F}{m}$ (2) This means the acceleration of the object varies inversely with its mass

Now, we are given the following data to calculate a constant force using (1):

$m_{1}=4 kg$

$a_{1}=5 m/s^{2}$

$F=m_{1}a_{1}$ (3)

$F=(4 kg)(5 m/s^{2)$ (4)

$F=20 N$ (5)

If we apply this same force calulated in (4) in another object with an acceleration of $a_{2}=2 m/s^{2}$ , its mass $m_{2}$ will be:

$F=m_{2}a_{2}$ (6)

$20 N=m_{2}2 m/s^{2}$ (7)

Finding $m_{2}$ :

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weeeeeb [17]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Which figure is the image produced by applying the composition T 0,3 o R0,90 to figure R?

Lyrx [107]

We are given original image R.

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Translation by (0,3) represents (x,y) --> (x, y+3) rule.

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The rule for counterclockwise rotation is (x,y) --> (-y,x).

Therefore, final rule for would be

(x,y) --> ( -y,x+3 )

Let us take a coordinate of R on y-axis as (0,-4).

Now if we apply rule (x,y) --> ( -y,x+3 ) we get

(0,-4) --> (-(-4), 0+3) = (4,3).

Let us check the figure with coordinate (4,3).

We can clearly see that Figure H has transformed coordinate (4,3).

<h3>Therefore, correct option is first option A. figure H.</h3>

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