I believe it is D. The lowest number on the y-axis is -4, and the highest is 0. -4<=y<=0
        
                    
             
        
        
        
Let, length and breadth of rectangle is L and B respectively.
It is given that :
The length rectangle is 4 cm more than 3 times the width of the rectangle.
L = 3B + 4  ......1 )
Also, area of square = area of the rectangle + 66 
L² = LB + 66
Putting value of L from 
L² = ( 3B + 4 )( B ) + 66
L² = 3B²  + 4B + 66
( 3B + 4 )² = 3B²  + 4B + 66
9B² + 16 + 24B = 3B²  + 4B + 66
6B² + 20B - 50 = 0
3B² + 10B - 25 = 0
3B² + 15B - 5B -25 = 0
3B( B + 5 ) -5( B + 5 ) = 0
B = 5/3 units
L = 3( 5/3 ) + 4
L = 5 + 4 = 9 units
Hence, this is the required solution.
 
        
             
        
        
        
Answer:
Step-by-step explanation:
cartesian plane :
quadrant 1 : both x and y are positive
quadrant 2 : x is negative, y is positive
quadrant 3 : both x and y are negative
quadrant 4 : x is positive and y is negative
(-2,4)......we have x is negative and y is positive...so we are in quadrant 2
(3,-1)....we have x is positive and y is negative...in quadrant 4
(-1,0) ...if u have a 0 in ur points, they do not lie in any quadrant because they are located on an axis....this is located on axis x
(1,2)....both are positive....located in quadrant 1
(-3,-5)...both are negative.....quadrant 3
 
        
             
        
        
        
I believe the answer is <span>$30 a week</span>
        
             
        
        
        
Answer:
a
Step-by-step explanation: