To check for continuity at the edges of each piece, you need to consider the limit as 
approaches the edges. For example,
has two pieces, 
and 
, both of which are continuous by themselves on the provided intervals. In order for 
to be continuous everywhere, we need to have
By definition of , we have 
, and the limits are
The limits match, so is continuous.
For the others: Each of the individual pieces of 
are continuous functions on their domains, so you just need to check the value of each piece at the edge of each subinterval.
Answer:
5A)36 5b)30(mark as brainliest)
Step-by-step explanation:
5a)6+6+6+6+12 = 36
5b)36-8=28
28+2 = 30
Answer:
x = 19.6
Step-by-step explanation:
If we need to find the value of x then first we need to
(7x-25) + (3x +9) = 180 (angles at the same side of transversal will be equal to 180 degree )
10x -16 = 180
10x = 180 +16
10x = 196
x = 196/10
x = 19.6
0.08 divided by 1.44 is 0.055555556
8 = letter
c = vowels
8 -c = consonants
_____________
c = 3
so, you've got three vowels
