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Aloiza [94]
4 years ago
14

Rectangular prism with a length, width, and height of 1/5 cm, 2/5 cm, 3/5 and cm, respectively

Mathematics
1 answer:
Bezzdna [24]4 years ago
5 0
3/4 with the main number divide it
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Tiffany uses 1/10 of her wages each month to buy company stock. Also she puts 1/20 of her wages in a savings account, and 1/15 i
Novosadov [1.4K]

Answer:

The fraction of Tiffany wages taken out for these purpose is \dfrac{13}{60} .

Step-by-step explanation:

Given as :

Let The wages earn by Tiffany = $x

Let The fraction of Tiffany wages taken out for purpose = $y

Tiffany uses \dfrac{1}{10} of her wages each month to buy company stock.

She puts \dfrac{1}{20} of her wages in a savings account .

She puts \dfrac{1}{15} of her wages into company pension plan

Now,

Total fraction of wages used by Tiffany = fraction used to buy company stock + fraction used in saving account + fraction used in pension plan

Or, y = \dfrac{1}{10} +  \dfrac{1}{20} +  \dfrac{1}{15}

Now taking LCM

Or, y = \dfrac{12 + 6 + 8}{120}

Or y = \dfrac{26}{120}

Or, y =  \dfrac{13}{60}

So, The fraction of Tiffany wages taken out for purpose = y = \dfrac{13}{60}

Hence, The fraction of Tiffany wages taken out for these purpose is \dfrac{13}{60} . Answer

8 0
3 years ago
Prove that angles opposite to equal sides of an isosceles triangle are equal.
ZanzabumX [31]

Answer:

Step-by-step explanation:

Take a triangle ABC, in which AB=AC.

Construct AP bisector of angle A meeting BC at P.

In ∆ABP and ∆ACP

AP=AP[common]

AB=AC[given]

angle BAP=angle CAP[by construction]

Therefore, ∆ABP congurent ∆ACP[S.A.S]

This implies, angle ABP=angleACP[C.P.C.T]

8 0
3 years ago
HELP PLEASE FAST WILL MARK BRAINLIEST
Butoxors [25]
5 customers are 19-
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7 0
3 years ago
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Rewrite 118 as a fraction in lowest terms.
Gnom [1K]
Last choice 1 9/50

118/100 =

(2 × 59)/(22 × 52) =

((2 × 59) ÷ 2) / ((22 × 52) ÷ 2) =

59/(2 × 52) =

59/50

Then

59 ÷ 50 = 1 and remainder = 9 =>

59 = 1 × 50 + 9 =>

59/50 =

(1 × 50 + 9) / 50 =

1 + 9/50 =

1 9/50
3 0
3 years ago
If c, m, and n are integers, which of the following are NOT possible values of m and n for the equation below? (Equation in pic)
kakasveta [241]

Answer: C. m = -2; n = -2

have:

x² + 4x + c = (x + m)(x + n)

⇔ x² + 4x + c = x² + (m + n)x + mn

⇒ m + n = 4

    mn = c

=>  M=-2, n=-2 arent possible

Step-by-step explanation:

6 0
3 years ago
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