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Mars2501 [29]
3 years ago
12

Which equation correctly describes the relationship between segment lengths in the given figure?

Mathematics
1 answer:
Readme [11.4K]3 years ago
5 0

Answer: Choice A

Step-by-step explanation:

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It’s should be about 320
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NEED HELP WORTH 100 POINTS SHOW YOUR WORK PLEASE
tia_tia [17]

Answer:

Q1:

-5\sqrt{27c^2}

-5\sqrt{27}\sqrt{c^2}

-5\times\sqrt{9} \sqrt{3} \sqrt{c^2}

-5\times3\sqrt{3}\sqrt{c^2}

-5\times3\sqrt{3}c

-15\sqrt{3}c

Q2:

5\sqrt{72}-3\sqrt{32}

5\sqrt{36} \sqrt{2} -3\sqrt{16} \sqrt{2}

5\times6\sqrt{2}-3\times4\sqrt{2}

30\sqrt{2}-12\sqrt{2}

18\sqrt{2}

Q3:

\sqrt{108yz}+3\sqrt{98yz}+2\sqrt{75yz}

\sqrt{36} \sqrt{3} \sqrt{yz} +3\sqrt{49} \sqrt{2} \sqrt{yz} +2\sqrt{25} \sqrt{3} \sqrt{yz}

6\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}+10\sqrt{3}\sqrt{yz}

16\sqrt{3}\sqrt{yz}+21\sqrt{2}\sqrt{yz}

Q4:

\sqrt{15n^2}\sqrt{10n^3}

\sqrt{15}n\sqrt{10n^3}

\sqrt{15}n\sqrt{10}\sqrt{n^2}\sqrt{n}

\sqrt{15}\sqrt{10}n^2\sqrt{n}

\sqrt{5}\sqrt{3}\sqrt{5}\sqrt{2}n^2\sqrt{n}

5\sqrt{3}\sqrt{2}n^2\sqrt{n}

5\sqrt{6}n^2\sqrt{n}

Q5:

\frac{\sqrt{3x^2y^3}}{4\sqrt{5xy^3}}

\frac{\sqrt{3}xy\sqrt{y}}{4\sqrt{5}y\sqrt{x}\sqrt{y}}

Cancel off \sqrt{x}:

\frac{\sqrt{3}y\sqrt{x}\sqrt{y}}{4\sqrt{5}y\sqrt{y}}

Cancel off y:

\frac{\sqrt{3}\sqrt{x}\sqrt{y}}{4\sqrt{5}\sqrt{y}}

Cancel off \sqrt{y} :

\frac{\sqrt{3}\sqrt{x}}{4\sqrt{5}}

Multiply \sqrt{5} on the numerator and denominator:

\frac{\sqrt{3}\sqrt{x}\sqrt{5}}{4\sqrt{5}\sqrt{5}}

\frac{\sqrt{15}\sqrt{x}}{20}

5 0
3 years ago
Please Help!!!
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The equation looks like this:

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where x is the number of pen you bought.

We solve it like this:
first, we subtract 8.50 from both sides:

17.50 =3.5*x

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so you purchased 5 pens.

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What is the first step when applying properties of operations to divide 73.85 by 4.1?
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False, true, & false
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