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Andrew [12]
3 years ago
9

1. A 100-foot rope is cut into 2 pieces (a and b). Piece a is 2ft less than 5 times the length of piece b. (a) What is the syste

m that models this situation? (b) Solve the system of equations
PLEASE HELP I WILL GIVE YOU 100PTS IF YOU HELP ME AND ANSWER THIS QUESTION
Mathematics
2 answers:
Mamont248 [21]3 years ago
6 0

Answer:

Represent the longer piece of the rope as (18 + x) and the shorter piece as x. The rope is 100 feet long, so:

(18 + x) + x = 100      Set up equation

18 + x + x = 100        Arrange like terms

18 + 2x = 100            Combine like terms

2x = 82                     Subtract 18 from both sides

x = 41                       Divide both sides by 2

Longer rope length: 12+ 31 =43 feet

Shorter rope length: 57 feet

Check: 59 + 41 = 100 feet

Step-by-step explanation:

tiny-mole [99]3 years ago
6 0

Answer/Step-by-step explanation:

100 divided by 2 = 50

rope a 50 divided by 10 = 5 - 2 = 3 ft

rope b 100 - 3 = 97

change 9 to 5

and change 3 to 43

a = 43

b = 57

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shepuryov [24]
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6 0
3 years ago
Read 2 more answers
Find an equation of the plane that contains the points p(5,−1,1),q(9,1,5),and r(8,−6,0)p(5,−1,1),q(9,1,5),and r(8,−6,0).
topjm [15]
Given plane passes through:
p(5,-1,1), q(9,1,5), r(8,-6,0)

We need to find a plane that is parallel to the plane through all three points, we form the vectors of any two sides of the triangle pqr:
pq=p-q=<5-9,-1-1,1-5>=<-4,-2,-4>
pr=p-r=<5-8,-1-6,1-0>=<-3,5,1>

The vector product pq x pr gives a vector perpendicular to both pq and pr.  This vector is the normal vector of a plane passing through all three points
pq x pr
=
  i   j   k
-4 -2 -4
-3  5  1
=<-2+20,12+4,-20-6>
=<18,16,-26>

Since the length of the normal vector does not change the direction, we simplify the normal vector as
N = <9,8,-13>

The required plane must pass through all three points.
We know that the normal vector is perpendicular to the plane through the three points, so we just need to make sure the plane passes through one of the three points, say q(9,1,5).

The equation of the required plane is therefore
Π :  9(x-9)+8(y-1)-13(z-5)=0
expand and simplify, we get the equation
Π  :  9x+8y-13z=24

Check to see that the plane passes through all three points:
at p: 9(5)+8(-1)-13(1)=45-8-13=24
at q: 9(9)+8(1)-13(5)=81+9-65=24
at r: 9(8)+8(-6)-13(0)=72-48-0=24
So plane passes through all three points, as required.

3 0
3 years ago
Help
kobusy [5.1K]

The equation of the line is y - 3 = 5(x - 8) ⇒ c

Step-by-step explanation:

The point-slope form of the linear equation is y-y_{1}=m(x-x_{1}) , where:

  • m is the slope of the line
  • (x_{1},y_{1}) is a point on the line

∵ The line passes through point (8 , 3)

∴ x_{1} = 8 and y_{1} = 3

∵ The slope of the line is 5

∴ m = 5

- Substitute these values in the form of the equation below

∵ y-y_{1}=m(x-x_{1})

∴ y - 3 = 5(x - 8)

The equation of the line is y - 3 = 5(x - 8)

Learn more:

You can learn more about the linear equations in brainly.com/question/1284310

#LearnwithBrainly

3 0
3 years ago
2x+5y=20. , -2x+20y=-90. one solution. infinity many ir no solution. use elimination to find your answer​
scoundrel [369]
2x+5y=20
X=10-2.5y

-2(10-2.5y)+20y=-90
-20+5y+20y=-90
25y=-70
Y=2.8

2(2.8)+5y=20

5.6+5y=20
5y=14.4
Y=2.88

CHECK:
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5 0
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A book had a length of 5 inches and a width of 8 inches. What is the perimeter of the book
andreev551 [17]
26 inches hope this helps

4 0
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