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nikitadnepr [17]
2 years ago
7

Find the measure of an angle whose complement is five times its measure.

Mathematics
1 answer:
ch4aika [34]2 years ago
4 0

Answer:

The measure of the unknown angle is 15°.

Step-by-step explanation:

Represent this angle by A.  Then the complement of A is 90° - A.

"Angle whose complement is five times its measure" would be expressed as

90° - A = 5A

Solve this for A by adding A to both sides:

90° = 6A.  Then A = 90°/6, or 15°

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Answer:

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Step-by-step explanation:

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Simplify (2n + 5) - (3n + 7) + (4n - 9).<br> -3n - 11<br> 3n - 11<br> -3n + 11<br> 3n + 11
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3 years ago
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(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5

x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}
 

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