The distance between the tree and the tower is 30√3m.
Justification:
<u>Let the situation be in a right angleABC form as shown in attached figure</u>.
<u>Given the height of the tower is 30m and the angle of depression to the base of the tree measure 30°</u>.
So, In ΔABC
tanθ = p/b
tan30° = 30/BC
1/√3 = 30/BC
BC = 30√3m.
Well its a pretty strong wind the answer is 75 mph
First you find out the distance without the wind which is 4x525 or 2,100
Now subtract 1800 from that and you get 300
But you’re still not done because 300 is the number of miles effected by the wind in the whole flight of 4 hours.
So just divide it by 4 and you get 75. So the wind is a 75 mph wind.
Brainliest my answer if it helps you out?
P^4, p^3,p^2,p is descending powers of p. Hope this helps!