3.7 x 0.25 please show me the steps on how to solve thank you

6/100 + 5/100 +80/100 +9/100

xz_007 [3.2K]

♡ The Question ♡

- 6/100 + 5/100 +80/100 +9/100

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Answer ♡

- 1

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ The Explanation/Step-By-Step ♡

- 6/100 + 5/100 + 80/100 + 9/100

Apply the fraction rule! --> a/c + b/c = a + b over c

6/100 + 5/100 + 80/100 + 9/100 = 6 + 5 + 80 + 9 over 100

Add the numbers: 6 + 5 + 80 + 9 = 100!

= 100/100 Apply the fraction rule! a/a = 1

a/a = 1 = 100/100 = 1

*୨୧ ┈┈┈┈┈┈┈┈┈┈┈┈ ୨୧*

♡ Tips ♡

- No tips provided!

4 0

3 years ago

Read 2 more answers

The team’s ratio of games won to games played was 3 to 8. If the team played 88 games, how many games did the team win? a. 11 ga

Gwar [14]

The correct answer would be B because 88 divided by 11 would be 8 and therfore it would justift that the ration would be equal to 88:33

6 0

3 years ago

Read 2 more answers

Find the next term of the following sequence. 25, 10, 4, ...

elixir [45]

The next term is 1, as it decreases by 15, then 6, and then by 3, if it continues the /2 pattern.

4 0

4 years ago

Read 2 more answers

A telephone service representative believes that the proportion of customers completely satisfied with their local telephone ser

zimovet [89]

Answer:

80% confidence interval for the difference in two proportions is [0.055 , 0.105].

Step-by-step explanation:

We are given that a telephone service representative believes that the proportion of customers completely satisfied with their local telephone service is different between the Northeast and the Midwest.

The survey included a random sample of 1200 northeastern residents and 1280 mid western residents. 44% of the northeastern residents and 36% of the mid western residents reported that they were completely satisfied with their local telephone service.

Firstly, the pivotal quantity for 80% confidence interval for the difference in two proportions is given by;

P.Q. = $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ~ N(0,1)

where, $\hat p_1$ = sample proportion of northeastern residents who were completely satisfied with their local telephone service = 0.44

$\hat p_2$ = sample proportion of mid western residents who were completely satisfied with their local telephone service = 0.36

$n_1$ = sample of northeastern residents = 1200

$n_2$ = sample of mid western residents = 1280

$p_1$ = true proportion of northeastern residents who were completely satisfied with their local telephone service

$p_2$ = true proportion of mid western residents who were completely satisfied with their local telephone service

Here for constructing 80% confidence interval we have used Two-sample z proportion statistics.

So, 80% confidence interval for the difference in two proportions, $(p_1-p_2)$ is ;

P(-1.2816 < N(0,1) < 1.2816) = 0.80 {As the critical value of z at 10% level of

significance are -1.2816 & 1.2816}

P(-1.2816 < $\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ < 1.2816) = 0.80

P( $-1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ < ${(\hat p_1-\hat p_2)-(p_1-p_2)}$ < $1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ) = 0.80

P( $(\hat p_1-\hat p_2)-1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ < $(p_1-p_2)}$ < $(\hat p_1-\hat p_2)+1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ) = 0.80

80% confidence interval for $(p_1-p_2)}$ =

[ $(\hat p_1-\hat p_2)-1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ , $(\hat p_1-\hat p_2)+1.2816 \times {\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2(1-\hat p_2)}{n_2} } }$ ]

= [ $(0.44-0.36)-1.2816 \times {\sqrt{\frac{0.44(1-0.44)}{1200} +\frac{0.36(1-0.36)}{1280} } }$ , $(0.44-0.36)+1.2816 \times {\sqrt{\frac{0.44(1-0.44)}{1200} +\frac{0.36(1-0.36)}{1280} } }$ ]