Question

What is the area of a parallelogram whose vertices are A(-12, 2), B6, 2). C(-2,-3), and D(-20, – 3)

Answer 1

Answer:

-35

Step-by-step explanation:

This value of "a" is exactly the y-coordinate of the vertex of the parabola

y = x%5E2+%2B+4x++-+31.

To find it, complete the square:

x%5E2+%2B+4x++-+31 = %28x%2B2%29%5E2+-+4+-+31 = %28x%2B2%29%5E2+-+35.

So, this value of "a" is a = -35.