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Levart [38]
3 years ago
6

Please help ASAP

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0
600x1.07^11 = 1262
11 Months
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How to solve this pythagoras theorem
My name is Ann [436]

Answer:

see explanation

Step-by-step explanation:

The hypotenuse is the longest side thus is (4x + 1)

The legs are 2x and (4x - 1)

Using Pythagoras' theorem, then

(4x + 1)² = (2x)² + (4x - 1)² ← expanding factors

16x² + 8x + 1 = 4x²  + 16x² - 8x + 1 , that is

16x² + 8x + 1 = 20x² - 8x + 1 ( subtract 20x² - 8x + 1 from both sides )

- 4x² + 16x = 0 ( multiply through by - 1 )

4x² - 16x = 0 ← factor out 4x from each term

4x(x - 4) = 0

Equate each factor to zero and solve for x

4x = 0 ⇒ x = 0

x - 4 = 0 ⇒ x = 4

Now x > 0, thus x = 4

2x = 2(4) = 8

4x - 1 = 4(4) - 1 = 16 - 1 = 15

4x + 1 = 4(4) + 1 = 16 + 1 = 17

Thus

perimeter = 8 + 15 + 17 = 40 cm

3 0
3 years ago
What is the distance between point A and point B?what is the ordered pair for each of the points plotted above?
Alekssandra [29.7K]

Answer:

A: (0,0), B: (3, -4), 5 units

Step-by-step explanation:

A: (0,0), B: (3, -4)

To find the distance, use the distance formula. Square-root((0-3)^2+(0-(-4))^2) ---> Square-root((-3)^2 + 4^2) ---> Square-root(9+16) ---> Square-root(25) ---> 5units.

6 0
3 years ago
Please I need this ASAP so can someone helpppppp
iris [78.8K]
AC = 8.9
BC = 6.5
(90% angle)
8.9 x 6.5 = <span>57.85
57.85/2 = 28.925
Area of ^ABC =  28.925 cm squared

DE = 55.1
55.1/ 11.02 = 5
DEF is 5 times as big as ABC
DF = 44.5
FE = 32.5
44.5 x 32.5 = 1446.25
1446.25/2 = 723.125
I am not positive but I believe DEF = 723.125 cm squared
Good Luck on the Test!! :D

</span>
7 0
3 years ago
What is the peremeter of this polygon? (With picture)
lyudmila [28]
Check the picture below.

so.. simply, use the distance formula, to get their length an add them up, and that's the perimeter of the polygon.


\bf \textit{distance between 2 points}\\ \quad \\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{ -1}}\quad ,&{{ 2}})\quad &#10;%  (c,d)&#10;&({{ 2}}\quad ,&{{ 4}})\\&#10;&({{ 2}}\quad ,&{{ 4}})\quad &#10;%  (c,d)&#10;&({{ 3}}\quad ,&{{ -2}})\\&#10;&({{ 3}}\quad ,&{{ -2}})\quad &#10;%  (c,d)&#10;&({{ -2}}\quad ,&{{ -3}})\\&#10;&({{ -2}}\quad ,&{{ -3}})\quad &#10;%  (c,d)&#10;&({{ -1}}\quad ,&{{ 2}})&#10;\end{array}\qquad &#10;%  distance value&#10;d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}

\bf -------------------------------\\\\&#10;d=\sqrt{[2-(-1)]^2+(4-2)^2}\implies d=\sqrt{(2+1)^2+(2)^2}&#10;\\\\\\&#10;d=\sqrt{3^2+2^2}\implies \boxed{d=\sqrt{13}}\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{(3-2)^2+(-2-4)^2}\implies d=\sqrt{1^2+(-6)^2}\implies \boxed{d=\sqrt{37}}\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{(-2-3)^2+[-3-(-2)]^2}\implies d=\sqrt{(-5)^2+(-3+2)^2}&#10;\\\\\\&#10;d=\sqrt{(-5)^2+(-1)^2}\implies \boxed{d=\sqrt{26}}

\\\\&#10;-------------------------------\\\\&#10;d=\sqrt{[-1-(-2)]^2+[2-(-3)]^2}\implies d=\sqrt{(-1+2)^2+(2+3)^2}&#10;\\\\\\&#10;d=\sqrt{(1)^2+(5)^2}\implies \boxed{d=\sqrt{26}}

so, those are their lengths, sum them all up, that's the polygon's perimeter.

4 0
3 years ago
Graph the line y=3x-8​
DaniilM [7]
Look at the picture

6 0
2 years ago
Read 2 more answers
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