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Levart [38]
3 years ago
6

Please help ASAP

Mathematics
1 answer:
scZoUnD [109]3 years ago
8 0
600x1.07^11 = 1262
11 Months
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What number is 50% out of 800??
Morgarella [4.7K]
400 since 50% is half
4 0
3 years ago
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Callie evaluated the expression 0.42 times 4.73 using the steps shown below. 0.42 times 4.73 = 1.26. 1.26 + 29.40 + 168.00 = 198
Andrej [43]

Answer:

The correct option is;

Callie multiplied incorrectly

Step-by-step explanation:

Here we have 0.42 × 4.73 = 1.9866 then

1.9866 + 29.4 + 168 = 199.3866

Therefore, from the question, we had 0.42 × 4.73 = 1.26 which is incorrect, meaning that Callie multiplied incorrectly

Apparently, Callie multiplied as follows;

0.42 × 3 = 1.26 but what was in the question was

0.42 × 4.73 which is equal to 1.9866.

4 0
3 years ago
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So far, Charlie has pures 456.6 Glories. He wants to burn a total of 500 calorierHow many more calories must Charlie burn?
klasskru [66]
Well if he’s burned 456.6 calories already and he needs to get to 500 then you would have to simply subtract 456.6 from 500
The equation: 500 - 456.6 = 43.4
Hope this helps!
4 0
3 years ago
How much meters per second did the cyclist travel from 8 a.M. To 10 a.M? (*TIP: 2 hours = 7200 seconds, 2 km= 2000 m). Give the
Mice21 [21]

Answer:

0.28 meters per second.

Step-by-step explanation:

We have that the speed formula is as follows:

v = d / t

In this case they tell us that the distance is 2 km the equivalent of 2000 meters and the time is 2 hours the equivalent of 7200 seconds, we replace and we are left with:

v = 2000/7200 = 0.28

Therefore it ran 0.28 meters per second.

4 0
3 years ago
Solve<br><br> 6x + 8 = 2x + 11<br><br> Thanks
hammer [34]
The equation given in the question should be written down first and then the process should start for solving and finding the value of the unknown variable "x".
6x + 8 = 2x + 11
6x - 2x = 11 - 8
4x = 3
x = 3/4
The value of the unknown variable "x" comes out to be 3/4. I hope the procedure for solving this equation is clear enough for you to understand. In future you can always use this procedure to get to the solution of similar problems.
6 0
3 years ago
Read 2 more answers
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