A 55.2 kg softball player moving 3.11 m/s slides across dirt with uk=0.310. How far does she slide before coming to a stop?
1 answer:
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Answer:
A. ) K =126. 7 J
B. ) h= 91.1 m.
Explanation:
A)
- Assuming no air resistance, once released by the pitcher, the speed must keep constant through all the trajectory, so the kinetic energy of the ball can be expressed as follows:
B)
- Neglecting air resistance, total mechanical energy must be the same at any point, so, if we choose the ground level as the zero reference level for the gravitational potential energy, and assuming that the ball attains this kinetic energy just before striking ground, this value must be equal to the gravitational potential energy just before be dropped, so we can write the following equality:
⇒ m*g*h = 126. 7 J
- Solving for h, we get:
The x and the y coordinates of the center of the mass of this system will be 43.1 m and 3.12 m respectively.
<h3>What is the center of mass?</h3>A location is established in relation to an object or set of objects in the center of mass. It is the system's average position across all of its components.
Given data;
There are three little objects that are densely spaced out in the x-y plane.;
The value of the masses
m₁=1.41 kg
m₂=2.55 kg
m₃=3.19 kg
Hence, the x and the y coordinates of the center of the mass of this system will be 4.31 m and 3.12 m respectively.
To learn more about the center of mass, refer;
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