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natta225 [31]
3 years ago
15

A 55.2 kg softball player moving 3.11 m/s slides across dirt with uk=0.310. How far does she slide before coming to a stop?​

Physics
1 answer:
just olya [345]3 years ago
4 0

Refer to the attachment

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Burka [1]
The structure and curvature of the Earth results in beams of sunlight glancing off the equator and reaching other areas of the Earth. This means that the areas at the equator receive more energy as sun's rays hit them directly.
Therefore, the answer is C.
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3 years ago
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This scientist focused his study on planetary motion. One of his laws is the planets orbit the Sun in elliptical patterns.
Savatey [412]
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8 0
3 years ago
A small metal sphere has a mass of 0.11 g and a charge of -21.0 nC . It is 10 cm directly above an identical sphere with the sam
GrogVix [38]

Answer:

A. the magnitude of the force between the spheres is 3.97 x 10⁻⁴ N

B. the magnitude of its initial acceleration is 5.83 m/s²

Explanation:

given information:

metal sphere's mass, m = 0.1 g = 1 x 10⁻⁴ kg

charge, q = -21 nC = -2.1 x 10⁻⁸

r = 10 cm = 0.1 m

What is the magnitude of the force between the spheres?

F₁₂ = k q₁q₂/r²

     = ( 9 x 10⁹) (-2.1 x 10⁻⁸)²/(0.1)²

     = 3.97 x 10⁻⁴ N

If the upper sphere is released, it will begin to fall. What is the magnitude of its initial acceleration?

mg - F₁₂ = ma

a = g - (F₁₂/m)

   = 9.8 - (3.97 x 10⁻⁴/1 x 10⁻⁴)

   = 5.83 m/s²

5 0
3 years ago
300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me​
Mandarinka [93]

Answer:

6KW

Explanation:

The computation is shown below:

We know that

Work done= m ×g× h

Here

W= 300×10×10

= 30000 J

= 30 KJ

And

Power= Work done ÷time taken

 P = 30000 ÷ 5

= 6000W

= 6KW

The above represent the answer

3 0
3 years ago
Can some please help me with this?
Lerok [7]

1) Current

2)  Atoms

3) Wire

4) Negative

5) Neutron

6) Shock

7) Switch

8) Static

9) Volt

10) Battery

11) Dam

12) Thomas Edison

13) Benjamin Franklin

14) Alessandro Volta

15) Michael Faraday

I would say that these would be your correct answers, btw I'm doing something that is close to the same right now

Hope this helps :)

6 0
3 years ago
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