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3 years ago

Advantages of high rupturing capacity fuses

Engineering

1 answer:

zlopas [31]3 years ago

4 0

Answer:

It clears high as well as low fault currents.

Do not deteriorate with age.

Having high-speed operation.

Provides reliable discrimination.

Require no maintenance.

Cheaper than other circuit interrupting devices with same rating.

Permit consistent performance.

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What's the real power if Vrms = 100V, Irms = 2A, and the circuit has a power factor of 0.8?

Temka [501]

Answer:

160 W

Explanation:

The relation is ...

Real Power = (pf)(V)(A)

= 0.8(100)(2) = 160 . . . . watts

7 0

3 years ago

7. You sometimes service vehicles with rust damage. It's safe to lift them on a two-post,

solong [7]

You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This is false.

Rust is an iron oxide, a typically reddish-brown oxide created when iron and oxygen react catalytically with moisture from the air or water. Iron(III) oxide-hydroxide and hydrous iron(III) oxides make up rust, which is often linked to the corrosion of refined iron.

Rusting is the chemical process that causes a red or orange coating to form on the surface of metals. Corrosion incorporates rusting. Steel and iron rust when they come into contact with oxygen and water, which are both necessary for rusting to take place.

It should be noted that when servicing vehicles with rust damage, It's not safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This can cause an accident.

Learn more about rust on:

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You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points.

True

False

8 0

2 years ago

A company specification calls for a steel component to have a minimum tensile strength of 1240 MPa. Tension tests are conducted

polet [3.4K]

Answer:

HV = 372.4 KGf/mm^2

$HR_C = 39.445$

Explanation:

given data:

minimum tensile strength = 1240 MPa

we knwo that $\sigma_{vrs}$ and brinell hardness number (HB} relation given as

$\sigma_{vrs} = 3.4 \times H.B$

$H.B = \frac{1240}{3.4} = 364.7$

1) relation betwen H.B and Rockwell is

$HR_C = 6.96 + 0.089 HB$

$HR_C = 6.96 + (0.089\times 365} = 39.445$

2) relation between HB and Vickers hardnes HV is given as

$HB \times 1.05 = HV + 10.5$

$HV = HB\times 1.05 - 10.5$

HV = 372.4 KGf/mm^2

4 0

4 years ago

Water "bubbles up" h2 = 9 in. above the exit of the vertical pipe attached to three horizontal pipe segments. The total length o

8_murik_8 [283]

The pressure needed at point (1) to produce the flow where water "bubbles up above the exit of the vertical pipe attached to three horizontal pipe segments is 0.750 psi.

<h3>What is Bernoulli's equation?</h3>

The Bernoulli's equation for incompressible fluid can be given as,

$P_1+\dfrac{1}{2}\rho v_1^2+\rho gh_1=P_2+\dfrac{1}{2}\rho v_2^2+\rho gh_2$

Here, ρ is density of fluid, g is acceleration due to gravity, (P) is the pressure v is velocity, h is height of elevation and subscript (1 and 2) is used for point 1 and 2.

Water "bubbles up" h2 = 9 in. Above the exit of the vertical pipe attached to three horizontal pipe segments.

The total length of the 1.75-in.- diameter galvanized iron pipe between point (1) and the exit is 21 inches. h3 = 18 in.

Reynolds number is,

$R_e=\dfrac{V_3D}{v}\\R_e=\dfrac{4.01\dfrac{0.75}{12}}{1.21\times10^{-15}}\\R_e=2.07\times10^4$

The formula for the ratio of pressure to radius, when pressure and velocity at point 2 is zero can be given as,

$\dfrac{p_1}{r}=z_2\left(f\dfrac{l}{d}+\sum k_L\right)\dfrac{v^2}{2g}-\dfrac{v_1^2}{2g}$

Here, f=0.039 and ∑K(L)=4.5. Put the values,

$\dfrac{p_1}{r}=\dfrac{7}{12}\left(0.03\dfrac{21}{0.75}+4.5-1\right)\dfrac{4.01^2}{2\times32.2}\\\dfrac{p_1}{r}=1.73\rm\; ft$

Put the value of r we get,

$p_1=62.4\times1.73\\p_1=108\rm\; ib/ft^2\\p_1=0.750\rm\; psi$

The pressure needed at point (1) to produce the flow where water "bubbles up above the exit of the vertical pipe attached to three horizontal pipe segments is 0.750 psi.

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5 0

2 years ago

The useful work potential of energy is called: a. Exergy b. Power c.Equilibrium d. Reversible work

tia_tia [17]

Answer:

a) Exergy

Explanation:

The useful work potential is called exergy. All practical process are ir-reversible process due to ir-reversibility ,the entropy of system increases and this leads to destroy the energy.

The rate of work is called power.

Reversible work is the maximum obtain work potential because it have all processes reversible.

So from this our option a is right.

7 0

3 years ago