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Nookie1986 [14]
2 years ago
6

7. You sometimes service vehicles with rust damage. It's safe to lift them on a two-post,

Engineering
1 answer:
solong [7]2 years ago
8 0

You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This is false.

<h3>What is rust?</h3>

Rust is an iron oxide, a typically reddish-brown oxide created when iron and oxygen react catalytically with moisture from the air or water. Iron(III) oxide-hydroxide and hydrous iron(III) oxides make up rust, which is often linked to the corrosion of refined iron.

Rusting is the chemical process that causes a red or orange coating to form on the surface of metals. Corrosion incorporates rusting. Steel and iron rust when they come into contact with oxygen and water, which are both necessary for rusting to take place.

It should be noted that when servicing vehicles with rust damage, It's not safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points. This can cause an accident.

Learn more about rust on:

brainly.com/question/1477535

#SPJ1

You sometimes service vehicles with rust damage. It's safe to lift them on a two-post frame-engaging lift without checking the vehicle lifting points.

True

False

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A market structure in which ther a single buyer
faltersainse [42]

Answer:

Monopsony

Explanation:

Kinda like a monopoly, except instead of one producer it is one buyer.

8 0
2 years ago
According to the eNotes, a program that eliminates sales and promotions in an effort to minimize the bullwhip effect would be ca
Ilia_Sergeevich [38]

Options: True or false

Answer:True, it will be called CRMWRONGEDLP.

Explanation:eNotes was founded in 1998 by Brad Satoris and Alexander Bloomingdale, to enable and enhance the ability of students to solve assignments as given and other home works,eNote is also used by students to prepare effectively and efficiently for examinations.

Since its launch eNote has been a great source of educational materials for students who have gained a lot in the use of its materials.

bullwhip effect is a concept in supply chain, where forcasts causes the supply chain to be inefficient, it usually starts from retailers who raise concern of high demands.

CRMWRONGEDLP, is the program that minimizes the bullwhip effects according to eNote.

7 0
3 years ago
How many kg / day of NaOH must be added to neutralize a waste stream generated by an industry producing 90,800 kg / day of sulfu
hram777 [196]

Answer:

74.12kg/day

Explanation:

Equation of reaction for the neutralization reaction of sodium hydroxide and sulfuric acid: 2NaOH + H2SO4 yields Na2SO4 + 2H2O

Mass of sulfuric acid produced per day = 90,800kg

Percentage of sulfuric acid in wastewater = 0.1%

Mass of sulfuric acid that ends up in wastewater per day = 0.1/100 × 90,800 = 90.8kg

From the equation of reaction, 2 moles of NaOH (80kg of NaOH) is required to neutralize 1 mole of H2SO4 (98kg of H2SO4)

80kg of NaOH is required to neutralize 98kg of sulfuric acid

90.8kg of sulfuric acid would be neutralized by (90.8×80)/98kg of NaOH = 74.14kg/day of NaOH

7 0
3 years ago
Read 2 more answers
36. What is mass? (4.4)
KatRina [158]

Answer:

Mass, in physics, quantitative measure of inertia, a fundamental property of all matter.

Explanation:

Mass is the matter that makes up objects

3 0
3 years ago
Consider a single bacterial cell as a discrete particle with a diameter of 1x10-6m and a specific gravity of 1.01. Assuming lami
Alinara [238K]

Answer:

Sedimentation is not a good method.

Explanation:

We need to apply Stoke laws and assume that is valid here.

So,

V_s= 418(G-1)d^2(\frac{3T+70}{100})

Replacing the values,

V_s= (418)(1.01-1)(10^-3)^3*(\frac{3*20+70}{100})\\V_s=5.434*10^-6mm/s

Here then we calculate the time,

t_{req}=\frac{x}{v}

Where x= Distance, v= velocity

t_{req}=\frac{1foot}{5.434*10^{-6}} = \frac{304.8}{5.434*10^{-6}}\\t_{req}=649.2days

To calculate the surface required we need first to calculate the volume through the volume,

So,

Q=4MGD=4*10^6*0.135 (ft^3/day)

Then,

V_{req} = Q*t\\V_{req}=4*10^6*0.134*649.2\\V_{req}=34.79*10^7ft^3

Here we can calculate the surface

S_{req}= \frac{Volume}{Distance}=\frac{34.79*10^7}{1}\\S_{req}=7987.8 Acres

<em>So, the requeriment of Area of tank and settlement time is huge, it's not a practical method.</em>

6 0
3 years ago
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