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trapecia [35]
2 years ago
11

Why are you asked to draw a sketch of a Bridge-Design on a graph sheet/A4 sheet?

Engineering
2 answers:
elena-s [515]2 years ago
4 0

Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.

Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.

It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.

Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.

Read related link on:

brainly.com/question/20689874

Alecsey [184]2 years ago
4 0

Answer:

Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.

Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.

It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.

Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.

Explanation:

You might be interested in
Which of the following can be used to create hydrogen? a. gasoline c. carbon monoxide b. carbon dioxide d. ammonia
Digiron [165]

Answer:

(d) Ammonia

Explanation:

When ammonia is kept at very high pressure and low temperature then its turns into liquid state but nitrogen and hydrogen is in gases state so we can easily find hydrogen as a byproduct from ammonia

Ammonia is considered as one of the primary candidate for the production of hydrogen

2NH_3\rightarrow 2N_2+3H_2

So option (d) will be correct option  

4 0
3 years ago
Which of following unit cell has the smallest atomic packing factor? (a) BCC unit cell (b) FCC unit cell (c) SC unit cell (d) HC
Dvinal [7]

Answer:

(c) SC unit cell

Explanation:

  • BCC (Body centered cubic ) : In this one atom is present at center of the cell and one at each corner the packing factor of the BCC is 68%
  • FCC( Face centered cubic ): In this one atom is present at the each faces and one at each corner the packing factor of FCC is 74 %
  • SC (Simple cubic ) : In this the atoms are present only at corner its packing factor is 52.4 %
  • HCP (Hexagonal closed pack ) its packing factor is 74.04 %

So from above discussion it is clear that simple cubic has smallest packing factor

4 0
3 years ago
Nitrogen enters a steady-flow heat exchanger at 150 kPa, 10°C, and 100 m/s, and it receives heat as it flows through it. Nitroge
diamong [38]

Answer:

A) Mach number at Inlet;M1 = 0.292

B) amount of heat received;Q_in = 105.59 KJ/kg

Explanation:

A) The formula for the speed of nitrogen at the inlet is;

C1 = √kRT1

Where;

k is a constant = 1.4

R is the gas constant of nitrogen R = 296.8 J/kg.K

T1 is the temperature at inlet = 10°C = 10 + 273 K = 283K

Thus;

C1 = √(1.4 * 296.8 * 283)

C1 = 342.9 m/s

Formula for mach number at inlet is;

M1 = V1/C1

We are given V1 = 100 m/s

Thus; M1 = 100/342.9

M1 = 0.292

B) We are given mach number at exit; M2 = 0.51

Also; V2 = 200 m/s

Thus;M2 = V2/C2

C2 = V2/M2 = 200/0.51

C2 = 392.16 m/s

Now, we know that;

C2 = √kRT2

So, 392.16 = √(1.4 * 296.8 * T2)

392.16² = 415.52*T2

T2 = 392.16²/415.52

T2 = 370.11 K

Now formula for steady flow balance equation is;

Q_in = =cp(T2 -T1) + [(v2)² - (v1)²]/2

Where Q_in is the amount of heat energy received and cp is the specific heat of nitrogen,= 1.040 KJ/kg.K

Plugging in the relevant values;

Q_in = 1.04(370.11 -283) + [(200)² - (100)²]/2](1KJ/Kg/1000m²/s²)

Q_in = 90.59 + 15

Q_in = 105.59 KJ/Kg

5 0
3 years ago
For problems 1 and 2, six luminaires, similar to Style E used in the Commercial Building, are to be installed in a room that is
BlackZzzverrR [31]

Answer:

7ft (2.13 m).

Explanation:

From the question above, the following parameters/data are given; the room dimension = 12 ft × 18 ft (∼3.7 m × ∼5.5 m), the floor-to-ceiling height = 9 ft (2.8 m) and the spacing ratio for the luminaire is 1:0.

Note that, we are not given the value or data for the height of the plane, therefore, we will make an assumption that the height of the plane = 2ft.

Hence, the work plane to luminaire distance = (9 - 2)ft = 7ft (2.13 m).

So, the maximum distance that the luminaires can be separated and achieve uniform illuminance is;

= the work plane to luminaire distance × spacing ratio for the luminaire.

= 7ft (2.13 m) × 1 = 7ft (2.13 m).

Thus, the maximum distance that the luminaires can be separated and achieve uniform illuminance is 7ft (2.13 m).

6 0
3 years ago
10. Aluminum-lithium (Al-Li) alloys have been developed by the aircraft industry to reduce the weight and improve the performanc
klio [65]

Answer:

C_Li=2.3 %

Explanation:

<u>solution:</u>

<em>we know that the average density of a two component alloy is given by:</em>

ρ_avg=100/(C_1/ρ_1+C_2/ρ_2)

2.47 g/cm^3=100/(C_Li/ρ_Li+(100-C_Li)/ρ_aL)

<em>solving for C_Li we get,</em>

C_Li=2.3 %

8 0
3 years ago
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