Why are you asked to draw a sketch of a Bridge-Design on a graph sheet/A4 sheet?
2 answers:
Engineers or architects can be asked to draw a sketch of a bridge-design on a graph sheet or A4 paper to communicate their ideas and scale their drawings.
Architectural sketches are about the communication of ideas. Engineers and architects use hand sketching to clarify elements of the design to the contractor or client.
It should be noted that drawings can also be drawn on a graph sheet or A4 paper to represent the detail before it's eventually constructed.
Scale drawings are used for the illustration of items that are not convenient to draw their actual size. In the construction industry, scales are used depending on the nature of the drawing. Drawings can be made on a graph or A4 paper due to the ease of printing, reproducing, and resizing the drawings.
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Answer:
Option C is correct.
Vs = 9 V, Rth = 30 ohms
Explanation:
In the circuit diagram, there are two sources, so, using superposition, we'll find voltage across A and B, Vab, with respect to each of the sources.
Taking the voltage source as primary source.
We will open circuit the current source just like it is presented in the first drawing of the 2nd image I have added to this solution.
By open-circuiting the current source, the three resistors R₁, R₂ and R₃ are in series.
This means that the Vab is the voltage across the R₃ resistor.
Using voltage divider rule,
Vab = (R₃/R₁ + R₂ + R₃) Vs₁
Vab = [40/(60 + 60 + 40)] (12)
Vab = 3 V
Taking the current source as the primary source.
We will now short circuit the voltage source as shown in the 2nd drawing of the 2nd image I have attached to this solution.
As shown in the 2nd drawing of the 2nd file I attached to this solution, the R₂ is in parallel with R₁ and R₃, that is R₂//(R₁ + R₃)
Using the current divider rule
Current in the (R₁ + R₃) branch = [R₂/(R₂ + (R₁ + R₃))] Is₂ = (60/(60 + 60 + 40)) (0.4) = 0.15 A
Vab = voltage across the R₃ resistor = IR₃ = 0.15 × 40 = 6 V
Total voltage across A and B, Vab = Vab due to Vs₁ + Vab due to Is₂ = 3 + 6 = 9 V
And for the Rth, we open-circuit the current source and short-circuit the voltage source simultaneously and look at the resistance of the setup from the AB terminal, as shown in the first drawing of the 3rd file attached to this solution.
It is evident that R₃ is in a parallel combination with (R₁ + R₂)
Rth = (R₁ + R₂)//R₃ = (60 + 60)//40 = 120//40 = (120× 40)/(120 + 40) = 30 ohms
The image of the thevenin equivalent of the circuit as seen from terminals AB is presented in the 2nd drawing on the 3rd image attached.
