I say yes because a whole number can be negative which makes it an integer
The expression of function g(x) is ![(\frac x2 - 1)^2](https://tex.z-dn.net/?f=%28%5Cfrac%20x2%20-%201%29%5E2)
<h3>How to determine the expression?</h3>
The function is given as:
![f(x) = x^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20x%5E2)
When the function is shifted right by 1 unit, the rule is:
f'(x) = f(x - 1)
So, we have:
![f(x) = (x - 1)^2](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%28x%20-%201%29%5E2)
When the function is compressed horizontally by a factor of 2, the rule is:
f'(x) = f(x/2)
So, we have:
![g(x) = (\frac x2 - 1)^2](https://tex.z-dn.net/?f=g%28x%29%20%3D%20%28%5Cfrac%20x2%20-%201%29%5E2)
Hence, the expression of function g(x) is ![(\frac x2 - 1)^2](https://tex.z-dn.net/?f=%28%5Cfrac%20x2%20-%201%29%5E2)
Read more about function transformation at:
brainly.com/question/13810353
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Answer:
v = 10
the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time
Step-by-step explanation:
Given;
function s(t) represents the position of an object at time t moving along a line.
s(1) = 62 at t1 = 1
s(5) = 102 at t5 = 5
Velocity v = distance/time
Average velocity v over time t is;
v = ∆s/∆t
v = [s(5) - s(1)]/[t5 - t1]
Substituting the given values;
v = (102 - 62)/(5 - 1)
v = 10
the average velocity of the object over the interval of time [1, 5 ] is 10 units per unit time
I can’t see the while question, can you please zoom out?.
Answer:
7.07
Step-by-step explanation:
√-50 is 7.071067