Question

What is the solution for the following system of linear equations? Give your answer in the form of an ordered pair.

Answer 1

Answer:

(1,1)

Step-by-step explanation:

3x + 2y = 5

4x − 9y = −5

Multiply the first equation by 4 and the second equation by -3 so we can eliminate x

4(3x + 2y) = 5 *4

Distribute

12x +8y = 20

-3(4x − 9y) = −5*-3

-12x +27y = 15

Add the two new equations together

12x +8y = 20

-12x +27y = 15

------------------------

35y = 35

Divide by 35

35y/35 = 35/35

y=1

Now we can find x

3x+2y =5

3x+2(1) =5

3x +2 =5

Subtract 2 from each side

3x+2-2=5-2

3x=3

Divide by 3

3x/3 = 3/3

x=1

(1,1)