Answer:
12x+4x-7y+45b+78a-44b+1a+1z+0d+1.1a+1.1a+2+2+2
Answer:
JL ≈ 32
Step-by-step explanation:
The triangle JKL has a side of JK = 24 and we are asked to find side JL. The triangle JKL is a right angle triangle.
Let us find side the angle J first from the triangle JKM. Angle JMN is 90°(angle on a straight line).
using the cosine ratio
cos J = adjacent/hypotenuse
cos J = 18/24
cos J = 0.75
J = cos⁻¹ 0.75
J = 41.4096221093
J ≈ 41.41°
Let us find the third angle L of the triangle JKL .Sum of angle in a triangle = 180°. Therefore, 180 - 41.41 - 90 = 48.59
Angle L = 48.59
°.
Using sine ratio
sin 48.59
° = opposite/hypotenuse
sin 48.59
° = 24/JL
cross multiply
JL sin 48.59
° = 24
divide both sides by sin 48.59
°
JL = 24/sin 48.59
°
JL = 24/0.74999563751
JL = 32.0001861339
JL ≈ 32
U add all the number together and then divide of how many numbers there is
Answer:
58°F, 20°F,11°F, 2°F , -2°F, -5°F
Answer:
2, 3, 5
Step-by-step explanation:
The question asking for the linear equation Suzie manipulated. The answer should be equal to the starting equation. So, we just need to manipulate the option to y= mx + c format.
1. y + 7x = 23
y= -7x +23 (false)
2. . –7x + y = 23
y= 7x + 23 (true)
3. 2y – 14x = 46
2y= 14x+ 46
y= 7x +23 (true)
4. y – 7x = –23
y= 7x - 23 (false)
5. 7x – y = –23
-y= -7x -23
y= 7x + 23 (true)
