Answer:
8.77777777778
Step-by-step explanation:
Answer:
VT = 50√3 , PT = 50
Step-by-step explanation:
Given
PV = 100
With reference angle 60°
hypotenuse (h) = 100
perpendicular (p) = ?
Now
Sin 60° = p/h
√3 / 2 = p / 100
p = √3 * 100 / 2
p = 50√3
Also
With reference angle 30°
hypotenuse (h) = 100
perpendicular (p) = ?
sin 30° = p/h
1/2 = p / 100
p = 100 / 2
p = 50
Hope it will help :)
a = amount invested at 5%
b = amount invested at 2%
now, we know the total invested by Mr Wilson was 20000, so whatever "a" and "b" might be, we know that a + b = 20000.
![a + b = 20000\implies b = 20000-a \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{5\% of a}}{\left( \cfrac{5}{100} \right)a}\implies 0.05a~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)a}\implies \begin{array}{llll} 0.02b\\\\ \stackrel{substituting}{0.02(20000-a)} \end{array}](https://tex.z-dn.net/?f=a%20%2B%20b%20%3D%2020000%5Cimplies%20b%20%3D%2020000-a%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B5%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B5%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%200.05a~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B2%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B2%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%200.02b%5C%5C%5C%5C%20%5Cstackrel%7Bsubstituting%7D%7B0.02%2820000-a%29%7D%20%5Cend%7Barray%7D)
now, we know the total of earned interest is 550 bucks, so then

Answer:
For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:
a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100
Step-by-step explanation:
Information given
We want to verify if he mean IQ of employees in an organization is greater than 100 , the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic for this case is given by:
(1)
The statistic calculated for this case 
The degrees of freedom are given by:
Now we can find the p value using tha laternative hypothesis and we got:
For this case the p value calculated is higher than the significance level used of 0.05 so then we have enough evidence to FAIL to reject the null hypothesis and the best conclusion for this case would be:
a) do not reject the null hypothesis and conclude that the mean IQ is not greater than 100