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Fynjy0 [20]
3 years ago
8

A student needs to make a circular cardboard piece with an area between 154 square inches and 616 square inches. The function f(

r) relates the area of the cardboard piece, in square inches, to the radius r in inches. Which of the following shows a reasonable domain for f(r)?
7 < r < 14

154 < r < 616

all positive integers less than 7

all positive integers between 14 and 154
Mathematics
1 answer:
Nezavi [6.7K]3 years ago
3 0
The area of the circle by definition is given by:
 f (r) =  \pi  * r ^ 2&#10;
 For f (r) = 154:
 154 =  \pi  * r ^ 2&#10;
 Clearing r we have:
 r ^ 2 = 154 / 3.14&#10;&#10; r =  \sqrt{154/3.14} &#10;&#10; r = 7
 For f (r) = 616:
 616 = \pi * r ^ 2
 Clearing r we have:
 r ^ 2 = 616 / 3.14 r = \sqrt{616/3.14} r = 14
 Answer:
 
a reasonable domain for f (r) is:
 
7 <r <14
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It has been found that women are excluded from social events with coworkers. One study at Company X, found that women only recei
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Answer:

Option C is correct.

The p-value in this case is the probability of getting data like that observed or more extreme (i.e., getting an observed invitation rate of 33% or higher) assuming that;

The social strategies did not increase the rate of invitations for female colleagues.

Step-by-step explanation:

The p-value is actually defined as the probability of obtaining results as extreme as the observed results in the statistical analysis provided that the null hypothesis is true.

The standing condition for the p-value definition is the assumption that the null hypothesis is true, then it is the probability of getting the extreme result (usually not due to just random chance), that is usually observed, being tested for and contained in the alternative hypothesis.

Normally, in hypothesis testing, especially one comparing two sets of data, the null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test. It usually maintains that, with random chance responsible for the outcome or results of any experimental study/hypothesis testing, its statement is true.

The alternative hypothesis usually confirms the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test. It usually maintains that significant factors other than random chance, affect the outcome or results of the experimental study/hypothesis testing and result in its own statement.

Since this test aimed to test whether the rate of invitation of women to outside work events after using the social strategies, the null hypothesis for the question would be that there is no significant difference in the rate of invitation of the women after using the social strategies while the alternative hypothesis would be that the social strategies worked and the rate invitation of women to outside of work events increased.

So, the null hypothesis that we need to assume was true in the p-value definition is that; the social strategies did not increase the rate of invitations for female colleagues.

This is option C!

Hope this Helps!!!

8 0
3 years ago
Niu has decorated x cards. He started with 24 stickers, and he used 4 stickers per card. Which expressions can we use to describ
Kisachek [45]

Answer:

24-4x

Step-by-step explanation:

We have been given that Niu has decorated x cards. He started with 24 stickers and he used 4 stickers per card. So stickers used in x cards will be 4x.

As initial number of stickers was 24, so we can find number of stickers left after decorating x cards by subtracting number of stickers used in x cards from 24.

\text{Number of stickers that Niu has left}=24-4x

Therefore, the expression 24-4x will represent the number of stickers that Niu has left after decorating x cards.


7 0
4 years ago
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Match the expression to its value.​
brilliants [131]

Answer:

1       a

2      b

3      c

4      d

Step-by-step explanation:

1b

2d

3c

4a

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What is the equation 9+10​
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One urn contains one blue ball (labeled B1) and three red balls (labeled R1, R2, and R3). A second urn contains two red balls (R
marusya05 [52]

Answer:

(a) See attachment for tree diagram

(b) 24 possible outcomes

Step-by-step explanation:

Given

Urn\ 1 = \{B_1, R_1, R_2, R_3\}

Urn\ 2 = \{R_4, R_5, B_2, B_3\}

Solving (a): A possibility tree

If urn 1 is selected, the following selection exists:

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

If urn 2 is selected, the following selection exists:

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

<em>See attachment for possibility tree</em>

Solving (b): The total number of outcome

<u>For urn 1</u>

There are 4 balls in urn 1

n = \{B_1,R_1,R_2,R_3\}

Each of the balls has 3 subsets. i.e.

B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]

So, the selection is:

Urn\ 1 = 4 * 3

Urn\ 1 = 12

<u>For urn 2</u>

There are 4 balls in urn 2

n = \{B_2,B_3,R_4,R_5\}

Each of the balls has 3 subsets. i.e.

B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]

So, the selection is:

Urn\ 2 = 4 * 3

Urn\ 2 = 12

Total number of outcomes is:

Total = Urn\ 1 + Urn\ 2

Total = 12 + 12

Total = 24

5 0
3 years ago
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