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melisa1 [442]
3 years ago
11

The difference of two numbers is 596 The smaller number is 716 what is the other number?​

Mathematics
1 answer:
Kitty [74]3 years ago
5 0

Answer

1,312 is the other number

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Identify the equation in slope-intercept form for the line that has the given slope and contains the given point.
Kisachek [45]
The answer I got was y=-12x+43.

Hope this helps!
5 0
3 years ago
Look at picture (15 point)
NNADVOKAT [17]

Answer:

<h2>x \sqrt{2}</h2>

Option C is the correct option

Step by step explanation

\sqrt{ \frac{22 {x}^{6} }{11 {x}^{4} } }

Reduce the fraction with 11

\sqrt{ \frac{2 {x}^{6} }{ {x}^{4} } }

Simplify the expression

\sqrt{2 {x}^{6 - 4} }

\sqrt{2  \: {x}^{2} }

Simplify the radical expression

x \sqrt{2}

Hope this helps...

Good luck on your assignment..

3 0
3 years ago
!!!PLEASE HELP!!!!
Vanyuwa [196]

Answer:

c. The solution to a system of equations is the point or points where they intersect

7 0
2 years ago
Mrs. Lavetan has 45 to complete her writing paper. She spend 10 and 1/8 min to planning her paper and 15 and 1/2 minutes weighti
Flura [38]

Answer: 20 minutes

Step-by-step explanation:

She has 45 mins to complete her writing paper.

She spends: 10\frac{1}{8} minutes to plan her paper.

She spends: 15\frac{1}{2} minutes writing rough drafts.

How much time left does she have?

45-(10\frac{1}{8} +15\frac{1}{2})

45-(10+15(\frac{1}{8}+\frac{1}{2}))

45-(25\frac{(1)(2)+(8)(1)}{(8)(2)})

45-(25\frac{2+8}{16} )

45-(25\frac{10}{16}) Simplify the fraction.

45-(25\frac{5}{8})

45-25(\frac{5}{8})

So she has approximately,

20\frac{5}{8} =\frac{165}{8}= 20 minutes.

8 0
4 years ago
Sinx =căn 2/3<br> sinx=5/4<br> sinx =1<br> sin3x=can3/2<br> sin(x-60)=-1/2<br> sin3x=1/2
mel-nik [20]

Answer:

Correct option is

B

0

D

−1

sinx+sin2x+sin3x

=sin(2x−x)+sin2x+sin(2x+x)

=2sin2xcosx+sin2x [ by using sin(A+B)=sinAcosB+sinBcosA and sin(A−B)=sinAcosB−sinBcosA ]

=sin2x(2cosx+1)........(i)

cosx+cos2x+cos3x

=cos(2x−x)+cos2x+cos(2x+x)

=2cos2xcosx+cos2x [By using cos(a−b)=cosa⋅cosb+sina⋅sinb and cos(a+b)=cosa⋅cosb−sina⋅sinb]

=cos2x(2cosx+1).....(ii)

∴(sinx+sin2x+sin3x)

2

+(cosx+cos2x+cos3x)

2

=1

sin

2

2x(2cosx+1)

2

+cos

2

2x(2cosx+1)

2

=1.......[From(i)(ii)]

⇒(2cosx+1)

2

=1

⇒2cosx+1=±1

∴cosx=0or−1

6 0
3 years ago
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