Answer:
use a calculator
Step-by-step explanation:
there for question b
I would say since thats $1500+ a month about 600 dollars, because she will have bills and then have to buy food drinks and alot more.
Answer:
£1837.5
Step-by-step explanation:
Given data
Cost of car P= £2100.
Rate r= 2.2%
Time t= 6 years
Now we want to find the worth after 6 years, let us apply the compound interest expression but this time for depreciation
A= P(1-r)^t
Substitute
A= 2100(1-0.022)^6
A= 2100*(0.978)^6
A= 2100*0.875
A= £1837.5
Hence the amount of the car after 6 years is £1837.5
Answer:
D
Step-by-step explanation:
If we look at the right side of the equation we see that the y-intercept is 2, so we will place a point on (0,2).
Next, we look to see if the slope of the graph if positive or negetive, and to see what is the slope (2x).
Finally, we look at the inequality if it is greater than (>), less than (<), greater than or equal to (_>), or less than or equal to (<_).
*Note the following:
if < then the line is dotted and the shading will be under the line.
if > then the line is dotted and the shading will be above the line.
if <_ then the line is solid and the shading will be under the line.
if _> then the line is solid and the shading will be above the line.*
It is a lot of information if you look at it, but with practice it can be made easier.
Answer:
b) The margin of error is approximately 3.24
e) The critical value is 1.7921.
Step-by-step explanation:
<u>Step(i</u>):-
Given sample size 'n' =20
Given sample standard deviation 's' = 10
<u><em> Margin of error </em></u>
<u><em>The margin of error is determined by</em></u>
<u><em /></u>
<u><em /></u>
<em>The level of significance ∝ =0.95</em>
<em>The degrees of freedom = n-1 = 20-1=19</em>
t₀.₉₅ = 1.729
Margin of error = 3.866
Step(ii):-
<u><em> Margin of error </em></u>
<u><em>The margin of error is determined by</em></u>
<u><em /></u><u><em /></u>
<u><em>Given another sample size n =30</em></u>
<em>The level of significance ∝ =0.95</em>
<em>The degrees of freedom = n-1 = 30-1=29</em>
t₀.₉₅ = 1.70
<u><em>Margin of error = 3.24</em></u>
