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Blizzard [7]
3 years ago
6

Question 2-4

Mathematics
1 answer:
Gnoma [55]3 years ago
8 0

Step-by-step explanation:

-x/3 < -4

-x < -12

x > 12

5x +11 ≤ -4

5x ≤ -4-11

5x ≤ -15

x ≤ -3

therefore, the solution is

x ≤ -3 or x > 12

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prisoha [69]

Answer:

i dont know

Step-by-step explanation:

4 0
3 years ago
The sum of two numbers, x and y, is 12. The difference of x and two times y is 6. What are the values of x and y?
ikadub [295]
We write to expressions since there are two unknown here which is x and y. The first expression is the <span>sum of two numbers, x and y, is 12.

x + y = 12

The second expression is that the </span><span>difference of x and two times y is 6.

x -2y = 6

Therefore, the values of x and y are 10 and 2.</span>
5 0
3 years ago
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Given the following formula, with A = 27 and t = 3, solve for r. <br> A=p(1+rt)
Nookie1986 [14]

Answer:

<h2>A.r=\frac{27-p}{3p}</h2>

Step-by-step explanation:

The given formula is

A=p(1+rt)

Where A=27 and t=3

To solve for r, first we need to move p

\frac{A}{p}=1+rt

Then, we move the term 1

\frac{A}{p}-1=rt

Finally, we move the factor t

\frac{\frac{A}{p}-1 }{t} =r

Replacing given values, we have

\frac{\frac{27}{p}-1 }{3} =r\\r=\frac{\frac{27-p}{p} }{3} \\r=\frac{27-p}{3p}

Thereofre, the right answer is A.

7 0
3 years ago
How do I factor out a constant before factoring out a quadratic? <br>Factor completely: 3w^2-3w-90
pantera1 [17]
3w^2-3w-90 =0 \ \ \:3 \\ \\w^2- w-30 =0 \\ \\a=1 , \ b= -1 , c= -30 \\ \\\Delta =b^2-4ac = (-1)^2 -4\cdot1\cdot (-30) =1+120=121 \\ \\w_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{1-\sqrt{121}}{2 }=\frac{ 1-11}{2}=\frac{-10}{2}=-5

w_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{1+\sqrt{121}}{2 }=\frac{ 1+11}{2}=\frac{12}{2}=6 \\ \\ Answer:\\ \\ w^2- w-30 =(x+5)(x-6)
 

3 0
3 years ago
HELP ME PLEASE! I NEED HELP, ASAP! THX
Mila [183]

Answer:

6

Step-by-step explanation: so 3x2 is 6 because you have 2 color and 3 different options of shirts.

6 0
3 years ago
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