If the zeroes of the polynomial x^3-3x^2+x+1 are a-b,a,a+b find a and b
1 answer:
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IF you mean 
, then the following would be a solution:
First add 16 to both sides of the equation:
Now divide both sides of the equation by 3:
Take the square root of both sides to solve for "X", or simply solve by inspection: "what number(s) can be squared to get 49?"
Answer: -7 and 7 So the smallest solution would be "-7"
First add 16 to both sides of the equation:
Now divide both sides of the equation by 3:
Take the square root of both sides to solve for "X", or simply solve by inspection: "what number(s) can be squared to get 49?"
Answer: -7 and 7 So the smallest solution would be "-7"
