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Irina-Kira [14]
2 years ago
14

Guía metodológica esmate octavo grado resuelta unidad 4 de el libro de texto ​

Mathematics
1 answer:
adoni [48]2 years ago
6 0

Answer:

methodological guy that made grade resolve unit 4 of the textbook

Step-by-step explanation:

sorry if I didn't

o siento si no ayude

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B. Limited choice

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A-1+a+a+a+a+3 into L cm
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sorry the question isn't obvious at all, can you please rectify?

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Find the product of the following expression.<br> 4(3x2 - 4x + 5)
Papessa [141]

Answer:

-16x + 44

Solution:

4(3×2 - 4x + 5)

= 4( 6 - 4x + 5)

=4( -4x + 11)

= -16x + 44

4 0
2 years ago
Three populations have proportions 0.1, 0.3, and 0.5. We select random samples of the size n from these populations. Only two of
IRINA_888 [86]

Answer:

(1) A Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3) A Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

Step-by-step explanation:

Consider a random variable <em>X</em> following a Binomial distribution with parameters <em>n </em>and <em>p</em>.

If the sample selected is too large and the probability of success is close to 0.50 a Normal approximation to binomial can be applied to approximate the distribution of X if the following conditions are satisfied:

  • np ≥ 10
  • n(1 - p) ≥ 10

The three populations has the following proportions:

p₁ = 0.10

p₂ = 0.30

p₃ = 0.50

(1)

Check the Normal approximation conditions for population 1, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.10=1

Thus, a Normal approximation to binomial can be applied for population 1, if <em>n</em> = 100.

(2)

Check the Normal approximation conditions for population 2, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.30=310\\\\n_{c}p_{1}=50\times 0.30=15>10\\\\n_{d}p_{1}=40\times 0.10=12>10\\\\n_{e}p_{1}=20\times 0.10=6

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50 and 40.

(3)

Check the Normal approximation conditions for population 3, for all the provided <em>n</em> as follows:

n_{a}p_{1}=10\times 0.50=510\\\\n_{c}p_{1}=50\times 0.50=25>10\\\\n_{d}p_{1}=40\times 0.50=20>10\\\\n_{e}p_{1}=20\times 0.10=10=10

Thus, a Normal approximation to binomial can be applied for population 2, if <em>n</em> = 100, 50, 40 and 20.

8 0
2 years ago
5) Solve: 2.4p + 6 = 48​
KatRina [158]

Answer:

p = 17.5

Step-by-step explanation:

This is the answer because:

1) First, we have to isolate x

2) To isolate x, first -6 from +6 and 48

+6 - 6 = 0

48 - 6 = 42

Equation: 2.4p = 42

3) Now we are left with 2.4p = 42

4) Next, divide 2.4 from 2.4 and 42

2.4/2.4 = 0

42/2.4 = 17.5

5) We are left with

p = 17.5

Therefore, the answer is p = 17.5

Hope this helps!

3 0
3 years ago
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