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Elanso [62]
2 years ago
11

I WANT SOLUTION AND EXPLANATION ANSWER IS GIVEN AT LAST!!!

Mathematics
2 answers:
Serga [27]2 years ago
6 0

let the numbers be x and y

x + y = 1600 ----*

12%x = 20%y

0.12x = 0.2y

y = <u>0</u><u>.</u><u>1</u><u>2</u><u>x</u>

0.2

y = 0.6x

substitute in * eqn

x + 0.6x = 1600

1.6x = 1600

x = 1000

then,

y = 0.6*1000

y = 600

the numbers are 1000 and 600

ra1l [238]2 years ago
3 0

\:\:\:\huge\mathbb\colorbox{black}{\color{white}{AnSwEr}}

Let the first number = x

then second number = 1600 - x

According to the condition in the question, we get

The explanation is in the attachment.

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Expand<br> c(3c - 3)<br> I need help on this
Rudik [331]

\\ \sf\longmapsto c(3c-3)

Apply distributive law

  • a(b-d)=ab-ad

\\ \sf\longmapsto 3c(c)-3(c)

\\ \sf\longmapsto 3c^2-3c

We can still take common

\\ \sf\longmapsto 3c(c-1)

4 0
2 years ago
Read 2 more answers
a boutique handmade umbrella factory currently sells 22500 umbrellas per year at a cost of 9 dollars each. in the previous year
sergij07 [2.7K]

Answer:

The maximum revenue of the two years is $ 394,500 .

Step-by-step explanation:

Given as :

The current number of selling of umbrellas = 22500

The price of each umbrellas = $ 9

So, The Total price of 22500 umbrellas at $ 9 per umbrellas = $ 9 × 22500

I.e The Total price of 22500 umbrellas at $ 9 per umbrellas = $ 202,500

Again ,

The total number of umbrellas sold previous year = 12000

The price of umbrellas = $ 16

So, The Total price of 12000 umbrellas at $ 16 per umbrellas = $ 16 × 12000

I.e The Total price of 12000 umbrellas at $ 16 per umbrellas = $ 192,000

So, The maximum revenue of the two years = $ 202,500 + $ 192,000

I.e The maximum revenue of the two years = $ 394,500

Hence The maximum revenue of the two years is $ 394,500 . Answer

3 0
3 years ago
The value of a school bus reduces from $512000 to $343000in 3 years. Find the
Eva8 [605]

Answer:

<em>The uniform rate of depreciation is $56,333 per year, or 11% per year.</em>

Step-by-step explanation:

<u>Rate of Depreciation</u>

If some object has a certain value P and after some time t its value decreases to Q, the rate of depreciation is a measure of how much its value changed per unit time.

It can be calculated as:

\displaystyle R=\frac{P-Q}{t}

It can also be expressed as a percentage, dividing the previous value by P.

The school bus reduces its value from $512,000 to $343,000 in 3 years, thus:

\displaystyle R=\frac{512,000-343,000}{3}

\displaystyle R=\frac{169,000}{3}

R = 56,333 $/year

Expressed as a percentage:

R = 56,333 / 512,000 = 0.11

R = 11%/year

The uniform rate of depreciation is $56,333 per year, or 11% per year.

8 0
3 years ago
The price of an item yesterday was $180. Today, the price rose to $279. Find the percentage increase.
olga55 [171]

Answer: 55%

1. 279 - 180 = 99

2. 99 divided by 180 = 0.55

3. 0.55 x 100 is 55.

55 is the percentage

3 0
3 years ago
Read 2 more answers
Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury and the stan
liq [111]

Answer:

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question, we have that:

\mu = 120, \sigma = 5.6

Find the probability that the individual's pressure will be between 119.4 and 121.4mmHg

This is the pvalue of Z when X = 121.4 subtracted by the pvalue of Z when X = 119.4. So

X = 121.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{121.4 - 120}{5.6}

Z = 0.25

Z = 0.25 has a pvalue of 0.5987

X = 119.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{119.4 - 120}{5.6}

Z = -0.11

Z = -0.11 has a pvalue of 0.4562

0.5987 - 0.4562 = 0.1425

0.1425 = 14.25% probability that the individual's pressure will be between 119.4 and 121.4mmHg.

8 0
2 years ago
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