Answer:
£1443.89
Step-by-step explanation:
To start you take the £1700 and multiply it by 4% (or .04) to find how much it depreciates for the first year. For the first year the depreciation £68 so the next year it will be worth £1632 ( £1700 - 68). You do the same thing for the second year but you start with the amount its worth now (£1632) and multiply again by the 4%. The depreciation for the second year is 65.28. Now you take what it was worth at the start of the year (£1632) and subtract the depreciation for the second year (65.28) to get £1566.72. You do the same process again for the third year to end up with a value of £1504.05. Now for the 4th year you will take the value of £1504.05 and again multiply by the depreciation rate of 4% to find the last amount of depreciation which is £60.16. Take your starting value for year 4 (£1504.05) and subtract the amount of depreciation (£60.16) to get your answer of £1443.89.
Answer:
12
Step-by-step explanation:
Answer:
The answer to your question is the second option, both coordinates should be negative.
Step-by-step explanation:
The point Hassam plotted was (-0.5, -0.25). If he wanted to plot point (0.5, 0.25):
-First, he should have counted two squares to the right
- then one square up.
Because both coordinates are positive this point must be in the first quadrangle not in the third.
Answer: F=1
Step-by-step explanation: Here
F(x)=x
Fx/x=x/x
F=1
Answer:
The probability that at least one of them is careful about personal information is 0.9744.
If the survey subjects volunteered to respond, then this a voluntary sampling and the estimated probability p may be biased, as only the people interested in the topic participate.
Given the subject of the survey, it is estimated that the ones who answered the survey are more careful about personal information and then the propability p is biased to a higher level than it should be if the sample was random.
Step-by-step explanation:
We can model this with a random variable, with sample size n=4 and probability of success p=0.6.
The probability that k individuals are more careful about personal information when using a public Wi-Fi hotspot in the sample is:

We have to calculate the probability that 1 or more are more careful about personal information when using a public Wi-Fi hotspot. This can be calculated as:

The probability that 1 or more individuals in the sample are more careful about personal information when using a public Wi-Fi hotspot is 0.9744.