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tia_tia [17]
2 years ago
6

Determine whether or not the pairs of triangles are similar and explain why.

Mathematics
1 answer:
Tom [10]2 years ago
6 0
No there not because each triangle has one bigger and one smaller and C. Is rotating different
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schepotkina [342]
1 meter is equal to 0.001 kilometers
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Kelsey babysits and earns a lat rate of $10 plus $1.50 per hour. How many hours did she babysit if she earned $16? (Write and so
Tasya [4]

Answer:

She babysitted for 4 hours.

Step-by-step explanation:

1.50x + 10 = 16

1.50x = 6

x = 4

Hope this helps!

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2 years ago
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Angle B= 45 degrees
Angle A = 45 degrees

A and B are congruent since they are alternate exterior angles
5x-15 = 2x +21
5x = 2x +36
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3 0
3 years ago
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Which percent is equivalent to
s344n2d4d5 [400]

Answer:

A

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7 0
3 years ago
Helppop!!A car and van are driving on a highway. The table shows the amount y (in gallons) of gas in the cars gas tank after dri
Korvikt [17]

Answer:

The car uses less gas

They use the same amount of gas after \frac{640}{7} miles

Step-by-step explanation:

Given

The table represents the car mileage

y = -\frac{1}{5}x + 31 --- The van

First, calculate the car's slope (m)

m = \frac{y_2 - y_1}{x_2 - x_1}

From the table, we have:

(x_1,y_1) = (60,13.5);\ \ (x_2,y_2) = (180,10.5)

So, we have:

m = \frac{10.5 - 13.5}{180 - 60}

m = \frac{-3}{120}

m = -\frac{1}{40}

Calculate the equation using:

y = -\frac{1}{40}(x - 60)+13.5

y = -\frac{1}{40}x + 1.5+13.5

y = -\frac{1}{40}x + 15

m = -\frac{1}{40} implies that for every mile traveled, the car uses 1/40 gallon of gas

Also:

y = -\frac{1}{5}x + 31 --- The van

By comparison to: y = mx + b

m = -\frac{1}{5}

This implies that for every mile traveled, the van uses 1/5 gallon of gas.

By comparison:

1/40 < 1/5

This means that the car uses less gas

Solving (b): Distance traveled for them to use the same amount of gas.

We have:

y = -\frac{1}{5}x + 31 --- The van

y = -\frac{1}{40}x + 15 --- The car

Equate both

-\frac{1}{5}x + 31 =-\frac{1}{40}x + 15

Collect like terms

\frac{1}{40}x -\frac{1}{5}x  =-31 + 15

\frac{1}{40}x -\frac{1}{5}x  =-16

Take LCM

\frac{x - 8x}{40} = -16

\frac{- 7x}{40} = -16

Solve for -7x

-7x = -640

Solve for x

x = \frac{640}{7}

5 0
3 years ago
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