Question

Write the equation of a line in point slope form that is PARALLEL 5x + 2y = 1 that passes through the point (- 2, - 3) .

Answer 1

Answer:

y = -5/2x - 13

Step-by-step explanation:

First, we have to find the slope of the original equation

Subtract 5x from both sides

5x + 2y = 1

- 5x         - 5x

2y = -5x + 1

Divide both sides by 2

2y/2 = (-5x + 1)/2

y = -5/2x + 1/2

The slope of this equation is -5/2, so -5/2 has to be in our new parallel equation

y = -5/2x + b

Plug in the given x and y

-3 = -5/2(-2) + b

-3 = 10 + b

Subtract 10 from both sides

-3 = 10 + b

- 10  - 10

b = -13

This makes our equation: y = -5/2x - 13