A) ![\sqrt[3]{x^4}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E4%7D)
B) Decimal Form:
0.87358046
sorry if i didnt get the 2nd one right i tired tho
mark brailiest please
:)
Answer:
Step-by-step explanation:
hello,
we need to evaluate f(15) so
f(15)=4*15-3=60-3=57
Hope this helps
Answer:
98.1% chance of being accepted
Step-by-step explanation:
Given:
sample size,n=56
acceptance condition= at most 2 batteries do not meet specifications
shipment size=7000
battery percentage in shipment that do not meet specification= 1%
Applying binomial distribution
<h3>P(x)=∑ᵇₐ=₀ (n!/a!(n-a)!)p^a (1-p)^(n-a)</h3>
In this formula, a is the acceptable number of defectives;
n is the sample size;
p is the fraction of defectives in the population.
Now putting the value
a= 2
n=56
p=0.01


=0.56960+0.32219+0.08949
After summation, we get 0.981 i.e. a 98.1% chance of being accepted. As this is such a high chance, we can expect many of the shipments like this to be accepted!
25.20, that might help you hopefully!
$21 because 3$x$7(numbers of days in a week)is $21. I hope this helps :)