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maksim [4K]
3 years ago
15

Solve the system of equations given below. 8x+4y=16 7y=15-x

Mathematics
1 answer:
Damm [24]3 years ago
8 0
1) first slove for X ( 7y=15−<span>x) to solve this first subtract 15 from both sides --> 
7y-15= -X ---> then multiply by -1 on both sides -----> -7y+15=x ( switch sides) so basically : </span>x=−7y+1<span>5
2) Then </span> Substitute x=-7y+15x=−7y+15 into 8x+4y=16 now solve steps below how to solve:
Start with the original equation ( 8x+4y=16)
Let x= -7y+15
<span>8(−7y+15)+4y=16 ----> simplify ----> −52y+120=16
Now solve for Y ( </span>−52y+120=1<span>6) steps:
</span>−52y=16−120 ( subtract 120 from both sides) & simplify by  16-120=−104
−52y=−104
now isolate Y divide both sides by -52 ----> y=2
Substitute y=2 into x=-7y+15
x= -7(2)+15 
x=1
your final answer :
x=1
y=2

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