Question

Solve the system of equations given below. 8x+4y=16 7y=15-x

Answer 1

1) first slove for X ( 7y=15−x) to solve this first subtract 15 from both sides --> 
7y-15= -X ---> then multiply by -1 on both sides -----> -7y+15=x ( switch sides) so basically : x=−7y+15
2) Then  Substitute x=-7y+15x=−7y+15 into 8x+4y=16 now solve steps below how to solve:
Start with the original equation ( 8x+4y=16)
Let x= -7y+15
8(−7y+15)+4y=16 ----> simplify ----> −52y+120=16
Now solve for Y ( −52y+120=16) steps:
−52y=16−120 ( subtract 120 from both sides) & simplify by  16-120=−104
−52y=−104
now isolate Y divide both sides by -52 ----> y=2
Substitute y=2 into x=-7y+15
x= -7(2)+15 
x=1
your final answer :
x=1
y=2