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3 years ago

14

72

1 answer:

Rzqust [24]3 years ago

6 0

Answer:

36

Step-by-step explanation:

The way to read this question would go: What is 72% of 50 because that will get you the number of correct solutions. When reading a statement like that, the word "of" means to multiply. However, before we multiply those two values we have to convert the value "72" into percent form. To do that you just divide it by 100 to get 0.72. Then following the statement, you would do 0.72*50 to get your final value of 36 correct questions

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2 years ago

Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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3 years ago

Read 2 more answers

If y=3 when x=9 find x when y=1<br> & if y=2 when x=0.5 find y when x=3

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