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Roman55 [17]
3 years ago
5

Find 46 percent of 80

Mathematics
1 answer:
umka2103 [35]3 years ago
4 0
36.8
..................................................................................
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Chandler's salary used to be $161,280. After changing the amount of time he works, he has begun earning $169,344. By what percen
Tju [1.3M]
Chandlers salary increased by 5 percent, to find this answer you take his new salary and divide it by its old and the decimal is the percentage increase
8 0
3 years ago
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Need help with this question ! Due soon*
Doss [256]

Answer:

x = 10, AB = 57

Step-by-step explanation:

In a trapezoid, the length of the median is one-half the sum of the lengths of the bases. From this, we have:

\frac{1}{2} (5x + 7 + 8x - 11) = 63

13x - 4 = 126

13x = 130

x = 10

5(10) + 7 = 50 + 7 = 57

5 0
2 years ago
In a group of 60 students, 12 students take Algebra I, 18 students take Algebra II, and 8 students take both subjects. How many
vodomira [7]
Since 8 students take both, that leaves only 4 students who take Algebra I alone.
Likewise since 8 students take both, that leaves 10 who only take Algebra 2
So out of the 60, twenty two are taking either Alg I Alg Ii or both.

That leaves 38 people who are not taking either.
b. 38

You can set this up using a 2 circle venn diagram.  Just be sure to put the 8 who take both in first.

4 0
3 years ago
Read 2 more answers
Can you help me please ​
Olenka [21]

Answer:

log_372 = 3.8928

Step-by-step explanation:

Given

log_38 = 1.8928

Required

Evaluate log_372

We have:

log_372 = log_3(8 *9)

Apply law of logarithm

log_372 = log_38 +log_39

Express 9 as 3^2

log_372 = log_38 +log_33^2

Evaluate the exponents

log_372 = log_38 +2log_33

log_33 = 1.

So:

log_372 = log_38 + 2 * 1

log_372 = log_38 + 2

Substitute log_38 = 1.8928

log_372 = 1.8928 + 2

log_372 = 3.8928

5 0
3 years ago
In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH
solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH   (*)

Consider triangles CBH and BCK. In these triangles,

  • ∠CBH ≅ ∠BCK (from equality (*));
  • ∠HCB ≅ ∠KBC, because m∠B = m∠C;
  • BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

5 0
3 years ago
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