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2 years ago

Please help!! Find two numbers whose sum is 26 and whose product is 168.

Mathematics

1 answer:

gavmur [86]2 years ago

3 0

The two numbers are 14 and 12.

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(25)2×100÷23+[24÷(13−5)]

hram777 [196]

Answer:

100*100/23+(24/8)

100*100/23+3

100*4.37+3

43.7+3

46.7

Step-by-step explanation:

7 0

2 years ago

Parallelogram or not ?

Zielflug [23.3K]

Answer:

I think so

Step-by-step explanation:

here's here's the definition of a parallelogram

"a four-sided plane rectilinear figure with opposite sides parallel."

3 0

2 years ago

Which of the following have the property that a(x)=a−1(x)? I. y=x II. y=1/x III.y=x^2 IV. y=x^3 A. I and II, only B. IV, only C.

valentina_108 [34]

Answer:

Correct answer:

A. I and II

Step-by-step explanation:

First of all, let us have a look at the steps of finding inverse of a function.

1. Replace y with x and x with y.

2. Solve for y.

3. Replace y with $f^{-1}(x)$

Given that:

$I.\ y=x \\II.\ y=\dfrac{1}x \\III.\ y=x^2 \\IV.\ y=x^3$

Now, let us find inverse of each option one by one.

I. y = x, a(x) = x

Replacing y with and x with y:

x = y

x = $a^{-1}(x)$ = $a(x)$ Hence, I is true.

II. $y =\dfrac{1}{x}$

Replacing y with and x with y:

$x =\dfrac{1}{y}$

$x=\dfrac{1}{a^{-1}(x)}$

$\Rightarrow a^{-1}(x) = \dfrac{1}{x}$

$a^{-1}(x)$ = $a(x)$ Hence, II is true.

III. $y =x^{2}$

Replacing y with and x with y:

$x =y^{2}\\\Rightarrow y = \sqrt x\\\Rightarrow a^{-1}(x) = \sqrt{x} \ne a(x)$

Hence, III is not true.

IV. $y =x^{3}$

Replacing y with and x with y:

$x =y^{3}\\\Rightarrow y = \sqrt[3] x\\\Rightarrow a^{-1}(x) = \sqrt[3]{x} \ne a(x)$

Hence, IV is not true.

Correct answer:

A. I and II

4 0

2 years ago

Part A Rewrite 0.5 as an exponential expression with a base of 2.

koban [17]

Answer:

$2^{-1}$

Explanation:

05/10

Simplifying

1/2

or 2^-1

Hope this helps you. Do mark me as brainlist

4 0

1 year ago

Which equation is y = 9x2 + 9x – 1 rewritten in vertex form?

Llana [10]

Answer:

1. y = 9(x+1/2)^2 -13/4

Step-by-step explanation:

y = 9x^2 + 9x – 1

first isolate the x terms

y = 9(x^2 +x) -1

then add 1/4 inside the brackets to make it a perfect square trinomial (half of the coefficient of the x term squared is how we get 1/4)

since we just added 1/4 we need to subtract what we just added to balance the equation. so 1/4 times 9 is 9/4 ( the number we just added to the equation). then you subtract 9/4 outside of the brackets.

y = 9(x^2 +x +1/4) -1 -9/4

then simplify

y = 9(x+1/2)^2 -13/4

6 0

2 years ago