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3 years ago

8

The function f(x) is a quartic function and the zeros of f(x) are -3,-1,4, and 6. Assume the leading coefficient of f(x) is 1. W

rite the equation of the quartic polynomial in standard form.

1 answer:

bekas [8.4K]3 years ago

4 0

Answer:

f(x) = x⁴-6x³-13x²+66x+72

Step-by-step explanation:

Factors are: (x+3)(x+1)(x-4)(x-6)

[(x+3)(x+1)][(x-4)(x-6)]

[x²+3x+x+3][x²-4x-6x+24]

(x²+4x+3)(x²-10x+24)

x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72

f(x) = x⁴-6x³-13x²+66x+72

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I assume your problem statement actually says

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2 years ago

If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?

bixtya [17]

Answer:

$T_{2} = 200$

Step-by-step explanation:

Given

Geometry Progression

$T_1 = 500$

$T_4 = 32$

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

$T_n = ar^{n-1}$

For first term: Tn = 500 and n = 1

$500 = ar^{1-1}$

$500 = ar^{0}$

$500 = a$

$a = 500$

For fought term: Tn = 32 and n = 4

$32 = ar^{4-1}$

$32 = ar^3$

Substitute 500 for a

$32 = 500 * r^3$

Make r^3 the subject

$r^3 = \frac{32}{500}$

$r^3 = 0.064$

Take cube roots

$\sqrt[3]{r^3} = \sqrt[3]{0.064}$

$r = \sqrt[3]{0.064}$

$r = 0.4$

Using: $T_n = ar^{n-1}$

$n = 2$ $r = 0.4$ and $a = 500$

$T_{2} = 500 * 0.4^{2-1}$

$T_{2} = 500 * 0.4^1$

$T_{2} = 500 * 0.4$

$T_{2} = 200$

<em>Hence, the second term is 200</em>

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