Question

The function f(x) is a quartic function and the zeros of f(x) are -3,-1,4, and 6. Assume the leading coefficient of f(x) is 1. Write the equation of the quartic polynomial in standard form.

Answer 1

Answer:

f(x) = x⁴-6x³-13x²+66x+72

Step-by-step explanation:

Factors are: (x+3)(x+1)(x-4)(x-6)

[(x+3)(x+1)][(x-4)(x-6)]

[x²+3x+x+3][x²-4x-6x+24]

(x²+4x+3)(x²-10x+24)

x⁴+4x³+3x²-10x³-40x²-30x+24x²+96x+72

f(x) = x⁴-6x³-13x²+66x+72