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1 year ago

Please help asap :((((

Mathematics

1 answer:

White raven [17]1 year ago

4 0

Answer: A

Step-by-step explanation:

Focus on what it is saying. It is saying that 5x IS LESS THAN OR EQUAL TO 15.

So we are looking for smaller numbers, that is, values of x, in order to make this statement true.

So on a number line we are looking for the left part shaded in.

Furthermore... notice that the sign has "or equal to". Thus the circle is going to be shaded in. The circle is not going to be open and empty. Through this we have eliminated answers B and C.

So the answer is A because— remember— the left side of the number line is shaded. It encompasses negative numbers. A negative number times 5 will definitely be less than 15.

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The temperature fell from 0 Degrees Fahrenheit to 15 and one-half Degrees Fahrenheit below 0 in 5 and three-fourths hours. Wen t

Kryger [21]

Answer:

The correct answer will be:

$-\dfrac{62}{23}$

Step-by-step explanation:

It is given that :

Initial temperature, $T_1 = 0^\circ F$

Final temperature,

$T_2 = -15\dfrac{1}{2}^\circ F\\\Rightarrow T_2 = -\dfrac{15\times 2+1}{2} ^\circ F\\\Rightarrow T_2 = -\dfrac{31}{2} ^\circ F$

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$5\dfrac{3}{4}\ hrs = \dfrac{5 \times 4+3}{4}\ hrs = \dfrac{23}{4}\ hrs$

Change in temperature per hour:

$\dfrac{\text{Difference of temperature}}{\text{Total Time Taken}}\\\Rightarrow \dfrac{T_2-T_1}{\text{Total Time Taken}}$

Putting the values of temperatures and time:

$\dfrac{\dfrac{-31}{2}-0}{\dfrac{23}{4}}\\\Rightarrow \dfrac{\dfrac{-31}{2}}{\dfrac{23}{4}}\\\Rightarrow \dfrac{-31 \times 4}{2 \times 23}} \text{---- Error done by Wen at this step}\\\Rightarrow \dfrac{-31 \times 2}{23}}\\\Rightarrow \dfrac{-62}{23}}$

The error done by Wen was during calculating the values of fraction.

So, the correct answer is : $\frac{-62}{23}}$ instead of $\frac{-713}{8}$

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2 years ago

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If the distance covered by an object in time t is given by s(t)=t^2+5t , where s(t) is in meters and t is in seconds, what is th

alisha [4.7K]

Answer:

E. 44 meters

Step-by-step explanation:

The function that models the distance covered by the object is

$s(t)=t^2+5t$

where s(t) is in meters and t is in seconds.

The distance covered by the object after 1 second is

$s(1)=1^2+5(1)=6m$

The distance covered by the object after 1 second is

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The distance covered between 1 second and 5 seconds is

50-6=44m

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Answer:

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Answer:

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