2/3 hour is 40 minutes. 1 3/4 hour is 1 hour and 45 minutes. So she spent 1 hour and 5 minutes or 1 1/12 hour longer doing homework.
Hey!
It looks like you meant:
![20x^3y+30x^2y^2](https://tex.z-dn.net/?f=20x%5E3y%2B30x%5E2y%5E2)
Then, we are going to change the expression, specially the exponents. The reason behind this is because we don't want anything to be cubed. Here's an example:
![\:a^{b+c}=a^ba^c](https://tex.z-dn.net/?f=%5C%3Aa%5E%7Bb%2Bc%7D%3Da%5Eba%5Ec)
![=20x^2xy+30x^2yy](https://tex.z-dn.net/?f=%3D20x%5E2xy%2B30x%5E2yy)
Factor out the common term, which is
![10x^2y](https://tex.z-dn.net/?f=10x%5E2y)
![=10x^2y\left(2x+3y\right)](https://tex.z-dn.net/?f=%3D10x%5E2y%5Cleft%282x%2B3y%5Cright%29)
Done!
Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
Answer:
3y + 2x = 5
Step-by-step explanation:
3x-2y = -2
2y = 3x + 2
y = (3/2)x + 1
Slope is 3/2
Slope of the Perpendicular line is -2/3
y = (-2/3)x + c
x = -2 , y = 3
3 = (-2/3)(-2) + c
3 = 4/3 + c
c = 3 - 4/3 = 5/3
y = (-2/3)x + 5/3
3y = -2x + 5
3y + 2x = 5
Answer:
8.2secs
Step-by-step explanation:
Given the expression for calculating the height as;
h = -16x^2+127x+80
Given h = 40
Substitute
40 = -16x^2+127x+80
-16x^2+127x+80 - 40 = 0
-16x^2+127x+40 = 0
16x^2-127x-40 = 0
Factorize
x = -(-127)±√(-127)²-4(16)(-40)/2(16)
x = 127±√16,129+2,560/32
x = 127±√18,689/32
x = 127±136.71/32
x = 127+136.71/32
x = 263.71/32
x = 8.24
Hence the required time to the nearest tenth is 8.2secs