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DiKsa [7]
3 years ago
8

Two times a number is more than 36.

Mathematics
1 answer:
alina1380 [7]3 years ago
6 0

Answer:

19

Step-by-step explanation:

19 x 2 = 38

Twice a quantity usually indicates to take two of the things in question; usually this indicates to multiply by 2. Thus "twice a number x" can be written symbolically as 2x. If this is part of a problem, say twice a number x is 6, then we can rewrite algebraically as 2x=6; dividing both sides by 2 yields x=3.

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How do I solve this I've been on this question for 3 weeks!!
Zigmanuir [339]

Answer:

c=3√5

Step-by-step explanation:

it appears the vertices of the inscribed quadrilateral,cuts the edges of the square at certain points that form right angles,with C being the hypotenuse.

c=√3²+6²

c=√9+36

c=√45=3√5

5 0
3 years ago
What is the length of z? (Round to the nearest tenth)
navik [9.2K]

Answer:

<em>z = 10.8</em>

Step-by-step explanation:

9^{2} + 6^{2} = c^{2}

81 + 36 = c^{2}

117 = c^{2}

c = \sqrt{117}

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4 0
3 years ago
The length of the escalator is 36 ft and the
beks73 [17]

Answer:

sin θ = 9 / 36 = 1/4

θ = 14.48 deg    (ans C)

8 0
2 years ago
g A sample of 3 items is chosen at random from a box containing 20 items, out of which 4 are defective. Let X be the number of d
professor190 [17]

Answer:

The variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

The variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

Step-by-step explanation:

The variable <em>X</em> is defined as, <em>X</em> = number of defective items in the sample.

In a sample of 20 items there are 4 defective items.

The probability of selecting a defective item is:

P (X)=\frac{4}{20}=0.20

A random sample of <em>n</em> = 3 items are selected at random.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 3 and <em>p </em>= 0.20.

The variance of a Binomial distribution is:

V(X)=np(1-p)

Compute the variance of <em>X</em> as follows:

V(X)=np(1-p)=3\times0.20\times(1-0.20)=0.48

Compute the standard deviation (σ (X)) as follows:

\sigma (X)=\sqrt{V(X)}=\sqrt{0.48}=0.693

Thus, the variance and standard deviation of <em>X</em> are 0.48 and 0.693 respectively.

Now compute the variance of (20 - X) as follows:

V(20-X)=V(20)+V(X)-2Cov(20,X)=0+0.48-0=0.48

Compute the standard deviation of (20 - X) as follows:

\sigma (20-X)=\sqrt{V(20-X)} =\sqrt{0.48}0.693

Thus, the variance and standard deviation of (20 - <em>X</em>) are 0.48 and 0.693 respectively.

3 0
3 years ago
Can yall help me please
Luda [366]
√896z^15/<span>√225z^6 

= </span>√896z^9/<span>√225

= </span>√64√14(z^4)<span>√z/15

= 8</span>√14(z^4)<span>√z/15

= (8z^4/15) * </span><span>√14z

x = 8</span>
7 0
3 years ago
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