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d1i1m1o1n [39]
3 years ago
6

HELP!!! ASAP!!!! IMAGES ATTACHED!! MATH SUCKS!!!!

Mathematics
1 answer:
melomori [17]3 years ago
4 0
The correct answer would be the first choice. For each picture drawn, the total cost increases by $34.50.
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Jan'ai was asked to determine the minimum for a function with zeros located at –1 and 5, which also has a y-intercept of (0, –25
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The answer is D. Here is the picture:

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3 years ago
Read 2 more answers
I need help with this​
OLga [1]

Answer:

121

Step-by-step explanation:

The sum of the angles inside a triangle is always 180. The missing angle in the triangle must then be 180 -74 -47 = 59 degrees. The angles on a straight line add up to 180 degrees so x + 59 = 180. x = 180-59 = 121

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3 years ago
Name ____________________________ Class________ Date ____________________________ Directions: Each diagram is formed by two para
hodyreva [135]

Step-by-step explanation:

How are we supposed to help...?

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3 years ago
PLS HELP WILL GIVE BRAINIEST! You are flying in an airplane that has 2 engines. The engines individually have a success rate of
Salsk061 [2.6K]

Answer:

.01%*

Step-by-step explanation:

Individually, they both have a rate of failure of 1%.

.01 x .01 = .0001

Therefore they have a combined probability of failure of .01%

*Disclaimer!!

I am not the best at this area in math so I would still reference against someone else's answer, but this is my best effort :)

4 0
3 years ago
A rancher wants to fence in an area of 1500000 square feet in a rectangular field and then divide it in half with a fence down t
VLD [36.1K]

Answer:

6000 ft

Step-by-step explanation:

Let length of rectangular field=x

Breadth of rectangular field=y

Area of rectangular field=1500000 square ft

Area of rectangular field=l\times b

Area of rectangular field=x\time y

1500000=xy

y=\frac{1500000}{x}

Fencing used ,P(x)=x+x+y+y+y=2x+3y

Substitute the value of y

P(x)=2x+3(\frac{1500000}{x})

P(x)=2x+\frac{4500000}{x}

Differentiate w.r.t x

P'(x)=2-\frac{4500000}{x^2}

Using formula:\frac{dx^n}{dx}=nx^{n-1}

P'(x)=0

2-\frac{4500000}{x^2}=0

\frac{4500000}{x^2}=2

x^2=\frac{4500000}{2}=2250000

x=\sqrt{2250000}=1500

It is always positive because length is always positive.

Again differentiate w.r.t x

P''(x)=\frac{9000000}{x^3}

Substitute x=1500

P''(1500)=\frac{9000000}{(1500)^3}>0

Hence, fencing is minimum at x=1 500

Substitute x=1 500

y=\frac{1500000}{1500}=1000

Length of rectangular field=1500 ft

Breadth of rectangular field=1000 ft

Substitute the values

Shortest length of fence used=2(1500)+3(1000)=6000 ft

Hence, the shortest length of fence that the rancher can used=6000 ft

3 0
4 years ago
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