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2 years ago

9

at a local drive-thru restaurant four out of every ten drinks sold are diet drinks if the restaurant sells 14,380 drinks in one

month how many would be diet drinks

1 answer:

Mamont248 [21]2 years ago

5 0

Answer:14.380÷10×4=5752

Step-by-step explanation:

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Mary leaves her house to take a walk. The graph shows the distance, d, in feet from her house that Mary is at any given time, t,

Mkey [24]

Answer:

It would be option A. 10 Minutes.

Step-by-step explanation:

If you look at the graph, the farthest point, and the time of 10 minutes meet at the point (10, 2,500)

(Really hoping this helps <3)

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3 years ago

Rectangular pyramid:volume 448 inches cubed, base edge 12 inches.;base length 8 inches

saw5 [17]

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3 years ago

Gregory predicts that 310 people will attend the spring play. There was an actual of 220 people who attended the spring play.wha

tia_tia [17]

The percent error is 29%. I posted the equation for percent error on your other question.

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3 years ago

Write the slope-intercept form of an equation that passes through the given points.<br> (4,1),(8,2)

Talja [164]

Answer:

y = 1/4x or y = 0.25x

Step-by-step explanation:

In this question, we are trying to write an equation with the given points.

To solve this question, we would use the slope formula: y2-y1/x2-x1

Find the slope by plugging in variables:

2-1/8-4

1/4 = m

The slope would be 1/4

Find the y intercept:

To find the y-intercept, you would need to use the slope you've found and one point, and plug it into the slope-intercept equation:

1 = 1/4(4) + b

Solve:

1 = 1/4(4) + b

1 = 1 + b

Subtract 1 from both sides

0 = b

This means that the y-intercept is 0.

Our equation will be: y = 1/4x

5 0

2 years ago

A surveyor leaves her base camp and drives 42km on a bearing of 032degree she then drives 28km on a bearing of 154degree,how far

ValentinkaMS [17]

Answer:

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

Step-by-step explanation:

The final position of the surveyor is represented by the following vectorial sum:

$\vec r = \vec r_{1} + \vec r_{2} + \vec r_{3}$ (1)

And this formula is expanded by definition of vectors in rectangular and polar form:

$(x,y) = r_{1}\cdot (\cos \theta_{1}, \sin \theta_{1}) + r_{2}\cdot (\cos \theta_{2}, \sin \theta_{2})$ (1b)

Where:

$x, y$ - Resulting coordinates of the final position of the surveyor with respect to origin, in kilometers.

$r_{1}, r_{2}$ - Length of each vector, in kilometers.

$\theta_{1}, \theta_{2}$ - Bearing of each vector in standard position, in sexagesimal degrees.

If we know that $r_{1} = 42\,km$ , $r_{2} = 28\,km$ , $\theta_{1} = 32^{\circ}$ and $\theta_{2} = 154^{\circ}$ , then the resulting coordinates of the final position of the surveyor is:

$(x,y) = (42\,km)\cdot (\cos 32^{\circ}, \sin 32^{\circ}) + (28\,km)\cdot (\cos 154^{\circ}, \sin 154^{\circ})$

$(x,y) = (35.618, 22.257) + (-25.166, 12.274)\,[km]$

$(x,y) = (10.452, 34.531)\,[km]$

According to this, the resulting vector is locating in the first quadrant. The bearing of the vector is determined by the following definition:

$\theta = \tan^{-1} \frac{10.452\,km}{34.531\,km}$

$\theta \approx 16.840^{\circ}$

And the distance from the camp is calculated by the Pythagorean Theorem:

$r = \sqrt{(10.452\,km)^{2}+(34.531\,km)^{2}}$

$r = 36.078\,km$

The surveyor is 36.076 kilometers far from her camp and her bearing is 16.840° (standard form).

5 0

3 years ago