Answer:
Step-by-step explanation:
This kinda looks like the limiting definition of a derivative.
Anyway, what we are doing with the f(2 + h) is evaluating f(x) with 2+h in place for x. That looks like this:
f(2 + h) = 2(2 + h) - 3 which simplifies to
f(2 + h) = 4 + 2h - 3 which simplifies to
2h + 1
From that we are subtracting f(2). What we are doing with that is evaluating f(x) with 2 in place for x. That looks like this:
f(2) = 2(2) - 3 which simplifies to
f(2) = 4 - 3 which simplifies to
f(2) = 1. Now put those together over h to get:
an aritmetic sequence increases by the same amount each time (if it decreases, then it increases by a negative number)
the common difference is the number that must be added to a term to get the next term
let's see if it increases by the same amount
-5 to -11 is increase of -6
-11 to -17 is increase of -6
-17 to -23 is increase of -6
-23 to -29 is increase of -6
so it appears to be aritmetic
common difference is -6
-29-6=-35
-35-6=-41
-41-6=-47
the next 3 terms are -35, -41, -47
The formula of a distance between two points:
We have:
substitute:
The answer will end up being c
