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Marina CMI [18]
3 years ago
5

Mrs. Davis’ gym class has 24 girls and 18 boys. She wants to separate the class into stations. Each station must have the same n

umbers of girls and boys.
What is the greatest number of stations Mrs. Davis can make if every student has to participate in a station?
Mathematics
1 answer:
s2008m [1.1K]3 years ago
5 0

Answer:

6 stations

Step-by-step explanation:

Find the GCD of 24 and 18 in order to get the greatest number of stations

GCD is 6

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Answer:

a) 0.96

b) 0.016

c) 0.018

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Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

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a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

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d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

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e) We have to find x such that P(X < x) = 0.75 ;

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               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

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Answer:

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Step-by-step explanation:

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